no i defo double checked it u couldnt have -3, i dont think it was 2log???
The first part of the question was to combine it into a single log
Then you had to solve that, but in the question it was expressed as two different logs. Putting in -3 into the calculator gives you a math error. So the only answer was 12
x^ isn't negative, but x is. The original equation was 2logx something.
In the same way you'd get a math error with a power like 400, so you multiply the log by 400, you get a math error with a negative power, so you apply the log's multiplier as an indice to square it and remove the negative
The first part of the question was to combine it into a single log
Then you had to solve that, but in the question it was expressed as two different logs. Putting in -3 into the calculator gives you a math error. So the only answer was 12
If you put -3 into the combined log ((-3)^2 / (-3+4)), you don't get a math error
Can someone plsss confirm , for the sum of U > sum of w , did u have to find a new first number and difference for the arithemetic because it was Un+1 it was just Un???
Also wasnt the period PIE/ A?
you could, if you wished have found the value of N with equality sign (this being critical value) and get something like 37.bla But 'is greater than' is asked for so rounding it up should give 38.
you could, if you wished have found the value of N with equality sign (this being critical value) and get something like 37.bla But 'is greater than' is asked for so rounding it up should give 38.
so u couldnt use the first number and D u had already found for part i ? u had to find it again with 1 , 2, 3 not using previous answer? this gave you A= 2.5 and D= 1
What about the separated logs?What were the equation?
2log base 3 (X) - log base 3 (X+4) = 2 Edit: the combined logs and the separated logs are equal so any manipulation, including squaring to remove the negative, will produce a correct answer
so u couldnt use the first number and D u had already found for part i ? u had to find it again with 1 , 2, 3 not using previous answer? this gave you A= 2.5 and D= 1
Yes you can use it but as far as I remember, U1 was 5 and Un+1 was Un+1.5 or so, giving a = 5 and d=1.5
That's probably the other later question with 3^(x-2)
2log base 3 (X) - log base 3 (X+4) = 2 Edit: the combined logs and the separated logs are equal so any manipulation, including squaring to remove the negative, will produce a correct answer
I got both 12 and -3, but said -3 is not valid since 2log base 3(-3) gives maths error. You could square the -3 but that's after manipulation and not the original equation. I really don't know. I wrote down 12 and -3 and then underlined 12
I got both 12 and -3, but said -3 is not valid since 2log base 3(-3) gives maths error. You could square the -3 but that's after manipulation and not the original equation. I really don't know. I wrote down 12 and -3 and then underlined 12