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2016 Edexcel C2 Morning exam[discussion thread]

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Original post by daria99
Note that question 6) ii) , had 3 values, original value for x was -14.4 but you also get 14.4. You may want to check that.


No, sin was -ve and the values needed to be 0<θ<3600<\theta<360

sin14.514\sin 14.5 \approx \frac{1}{4}
(edited 7 years ago)
Original post by X_IDE_sidf
No, sin was -ve and the values needed to be 0<θ<3600<\theta<360

sin14.5=14\sin 14.5 = \frac{1}{4}

Got 194.5 and 345.5 for that one.
Original post by Atiq629
Got 194.5 and 345.5 for that one.


as did I
it was cruel 2wo hard math exam papers shaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaan edexcel
Reply 104
For the last question I skipped part (a) and did the other parts because the answer was in the page, would I still get the marks?
Original post by Reda2
For the last question I skipped part (a) and did the other parts because the answer was in the page, would I still get the marks?


yes, you are the reason that the answers to those parts are written on the paper.
Original post by stephaniecheung
that's not the answer you forgot to put it back into the P :tongue:


What are you talking about? This is for the second derivative, to check that x was a minimum
http://www.ipetitions.com/petition/allow-arsey-to-release-edexcel-maths-solutions

COME ON GUYS SIGN THE PETITION TO ALLOW ARSEY TO RELLEASE EDEXCEL A LEVEL MATHS SOLUTIONS YEAR ON YEAR !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
A pretty good paper thank God , except the binomial **** it went fine and made a calculater mistake when finding x in the last question. Arsey ain't doin anymore model papers too
Reply 110
can anyone remember the final calculation for solving x, question 9. I never simplified it to 17 but can't remember if my solution was the equivalent
For the sin one, I used a CAST diagram but then I drew a graph to help double check my answers. The answers that I got was right (i think looking at what most people got), but I was wondering whether my method (especially the graph to double check) will be accepted?
Reply 112
For the log question i got x = -2.19 but i had a brain fart and put that it also = 0, will i lose marks for this?
Original post by puPper
For the log question i got x = -2.19 but i had a brain fart and put that it also = 0, will i lose marks for this?


How many marks was it? It's hard to say, but I think you might as it is actually not a solution. Plus the question said give your 'answer' (not answers) to 2 dp. If you're lucky they may ignore the 0.
Reply 114
can anyone recall what P was equal to in terms of x at the start of question 9c?
Original post by shayefc
can anyone recall what P was equal to in terms of x at the start of question 9c?


http://www.thestudentroom.co.uk/showthread.php?t=4117221&page=4&highlight=&p=65151283#post65151283

ignore me, P=1000x+x12(4π+3633) P= \frac{1000}{x} + \frac{x}{12}(4\pi + 36 - 3\sqrt{3})

dPdx=112(4π+3633)1000x2\frac{dP}{dx} = \frac{1}{12}(4\pi +36 - 3\sqrt{3})-\frac{1000}{x^2}

d2Pdx2=2000x3\frac{d^2P}{dx^2} = \frac{2000}{x^3}
(edited 7 years ago)
Reply 116
can anyone recall what the Perimeter was in terms of x pls
Original post by shayefc
can anyone recall what the Perimeter was in terms of x pls


Original post by X_IDE_sidf
http://www.thestudentroom.co.uk/showthread.php?t=4117221&page=4&highlight=&p=65151283#post65151283

ignore me, P=1000x+x12(4π+3633) P= \frac{1000}{x} + \frac{x}{12}(4\pi + 36 - 3\sqrt{3})

dPdx=112(4π+3633)1000x2\frac{dP}{dx} = \frac{1}{12}(4\pi +36 - 3\sqrt{3})-\frac{1000}{x^2}

d2Pdx2=2000x3\frac{d^2P}{dx^2} = \frac{2000}{x^3}


Please read
Please could someone post/try to remember the questions!
Is it just me or is the mark scheme that the guy posted on this thread missing 12 marks?

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