Basically firstly As has 5 outer shell electrons so draw the atom with the outer shell electrons somewhere on the page, then draw the Fluorine atoms on the As, simple basic covalent bonding diagram. Hence you can see that there are no free electrons on the atom so there are 5 bonding pairs. Let me know if you dont understand.
With ClF2+ . How do you know there are 2 lone pairs left?
Your method is fundamentally correct.
Chlorine = 7 electrons 2 x F = 2 electrons subtract one for the positive charge Total electrons = 8 = four pairs, two of which are used for bonding leaving two lone pairs. Electron domains = 4 = tetrahedral Ionic shape = bent or angular with two lone pairs.
Chlorine = 7 electrons 2 x F = 2 electrons subtract one for the positive charge Total electrons = 8 = four pairs, two of which are used for bonding leaving two lone pairs. Electron domains = 4 = tetrahedral Ionic shape = bent or angular with two lone pairs.
Yeah got it cheers Do you mind helping me with another qs:
An ultrasound imaging agent has the formula C4F10It can be made by the reaction of butane and fluorine as shown in the followingequation.C4H10 + 10F2 →C4F10 + 10HFCalculate the percentage atom economy for the formation of C4F10 in this reaction.Give your answer to three significant figures. Where does 238 come from?
Yeah got it cheers Do you mind helping me with another qs:
An ultrasound imaging agent has the formula C4F10It can be made by the reaction of butane and fluorine as shown in the followingequation.C4H10 + 10F2 →C4F10 + 10HFCalculate the percentage atom economy for the formation of C4F10 in this reaction.Give your answer to three significant figures. Where does 238 come from?
Chlorine = 7 electrons 2 x F = 2 electrons subtract one for the positive charge Total electrons = 8 = four pairs, two of which are used for bonding leaving two lone pairs. Electron domains = 4 = tetrahedral Ionic shape = bent or angular with two lone pairs.
Hi,
I use this method myself and works fine but how would you determine the shape if you are given a formula such as NH3? Im unsure how this works since either N or H could be the central element?
In this case N is the central atom with 3 H bonded to it. It would form 3 bonded pairs and 1 lone pair... So it's either trigonal pyramidal/ terahedral depending on what shapes you learnt.