Can anyone help me with this question please? (topix 3 redox)
7. Write balanced equations for these redox reactions. State which element is oxidized and which is reduced in each example. a) Fe and Br2 to give FeBr3
Overall equation: ………………….
Element oxidized: …………………
Element reduced: ………………
I know that Fe has oxidized because its oxidation state went from 0 to 3+
and that Br has been reduced as its oxidation state went from 0 to -1 (single atom)
And for the half equations i got: Fe ---> Fe^3+ + 3e^- & 3e^- + 3Br ----> Br3^-
same number of electrons in both half equations so it should make
Fe + 3Br ----> Fe^3+ + Br3^-
but the mark scheme says:2Fe(s) + 3Br2 (l) ----> 2FeBr3(s)
Can someone explain what i did wrong? is it because i changed the Br2 into Br?
Yes that was the mistake because bromine MOLECULES(Br2) are reduced, not bromine atoms.
Hello everyone!Could anyone please explain me why the answer is B ?- A sample of swimming pool water contains 0.482 ppm of chlorine. This is equal to a percentage of:A. 0.000482B. 0.0000482C. 0.00000482D. 0.000000482
0.482/1000000 *100 = B , dont think u need to know this for new spec
Yes that was the mistake because bromine MOLECULES(Br2) are reduced, not bromine atoms.
Thanks for your help! I have one question tho say an atom doesn't reduce or oxidize it stays the same. Do i have to make a half equations for it? example F2 + H2O ---> HF + O2 I know that the oxygen has oxidized and the F2 has reduced but hydrogen stays the same. do i just make half equations on F2 and O2 and ignore H2 but include it in the overall equation?
This is a covalent bond in which both of the electrons come from the same atom. It is represented by an arrow ----> from the atom providing the pair of electrons going towards the atom without a full octet (empty orbital)
Thanks for your help! I have one question tho say an atom doesn't reduce or oxidize it stays the same. Do i have to make a half equations for it? example F2 + H2O ---> HF + O2 I know that the oxygen has oxidized and the F2 has reduced but hydrogen stays the same. do i just make half equations on F2 and O2 and ignore H2 but include it in the overall equation?
No. hydrogen stays the same so they are spectator ions. you dont include them in the overall ionic equation. the overall ionic equation would be: 2o^2- +2f2--->4f^- +o2
No. hydrogen stays the same so they are spectator ions. you dont include them in the overall ionic equation. the overall ionic equation would be: 2o^2- +2f2--->4f^- +o2