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Edexcel IGCSE Mathematics A - Paper 3H - 2016 - Unofficial Mark Scheme

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Reply 180
I got every question right i think
We have to get ready for a hard 4H....
Original post by _Xenon_
I got every question right i think


Fair play, most of my school found this one as the "easier paper", if the next one is this standard then A* here I come!
Reply 183
correct me if I'm wrong but on the volume sphere and cube question:

if the lengths of the cube were 4.5, then they have to be in the upper bound (4.55cm)
therefore for maximum spheres, the radius of the spheres is in the lower bound (3mm so 2.5mm)
and convert mm into cm by dividing by 10 so 0.25cm.
then find volume of cube (4.55) cubed which is 94.196375, and the volume of the sphere (4/3 pi r cubed) so 0.06544984695. Then its 94.196375 divided by 0.06544984695 which equals 1439....
Reply 184
Original post by _Xenon_
I got every question right i think


why dont you complete the markscheme then
Original post by _Xenon_
I got every question right i think


safe m8
I got the volume as 256? I also got the spheres as 18 and the angle AH made with the plane as 25.0??
Reply 187
Original post by 18Moranm
I got the volume as 256? I also got the spheres as 18 and the angle AH made with the plane as 25.0??


how did you get 256
Reply 188
Original post by izak
why dont you complete the markscheme then


I am trying to but i can't remember ALL the questions or the question numbers.
People need to help me out?!!!

Area of shaded region question?
The trapezium one?
...
(edited 7 years ago)
Original post by memequeen69
3x-4y=19


How? not in a rude way just curious asI couldn't do this one
what was 38 the answer to?
Reply 191
Original post by izak
how did you get 256


what did you get for the interqutel range 20 ?

and the size of angle bettwen AH and the plane efgh was it 24.1 ??
For question two they said the following:
T is the total number of pens
X is a small box
Y is a big box
There are 4 pens in The small boxes and 10 pens in The big ones
I believe the answer was: T=4X+10Y
(3 marks)
(edited 7 years ago)
Original post by _Xenon_
I am trying to but i can't remember ALL the questions or the question numbers.
People need to help me out?!!!

Area of shaded region question?
The trapezium one?
...


I got x=8 for trapezium one and part a was just a show that, I think it was 18
Original post by izak
first 2 right, gradient had to be an integer, had to turn 3100 into percentage


yes sorry you are right the percentage rounded to 52%
Reply 195
Original post by mathstc
For question two they said the following:
_T_ is the total number of pens
_X_ is a small box
_Y_ is a big box
There are _4_ pens in The small boxes and _10_ pens in The big ones
I believe the answer was: _T=4X+10Y_
(3 marks)


Ooo i got it wrong. I wrote 2.5xy i think
Reply 196
Original post by _Xenon_
I am trying to but i can't remember ALL the questions or the question numbers.
People need to help me out?!!!

Area of shaded region question?
The trapezium one?
...


umm you find the area of the circle and the area of trap then - the area of circle from the area of trap youll find the area of shaded
also what was question 10 again?
Original post by zendu
correct me if I'm wrong but on the volume sphere and cube question:

if the lengths of the cube were 4.5, then they have to be in the upper bound (4.55cm)
therefore for maximum spheres, the radius of the spheres is in the lower bound (3mm so 2.5mm)
and convert mm into cm by dividing by 10 so 0.25cm.
then find volume of cube (4.55) cubed which is 94.196375, and the volume of the sphere (4/3 pi r cubed) so 0.06544984695. Then its 94.196375 divided by 0.06544984695 which equals 1439....


It was to nearest 0.5cm so incorrect rounding
Reply 199
Original post by _Xenon_
Ooo i got it wrong. I wrote 2.5xy i think


so T=4x+10y there is no _

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