m1 question

Question is, a particle of m kg slides down a smooth plane inclined at an angle of 30 degrees to horizontal. Find the acceleration down the plane.

Seems like no informaton is given.

I have got to
F = MA
so mgsin30 = MgA but thats it?

Well, resolving component of weight acting down the slope (the only force acting) is $mg \sin 30^{\circ}$.
$F=ma \Rightarrow mg\sin 30^{\circ}=ma$. I think you can do the rest?
I didn't read properly that you have already wrote this down, the mass on either side of the equation cancel as they are exactly the same.

if the mass cancel isnt it sin 30 = a so a is 0.5? but thats not the case