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Finding a carestian equation (parametric differentiation)

So the question is

X = cos^3 x
y = Sin^3 x

im baffled, by the power of 3, here, how do i find a cartesian equation frmo this, it does give me a suttle hint by saying find x^2/3
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Avatar for Zacken
Zacken
22
Original post by SunDun111
So the question is

X = cos^3 x
y = Sin^3 x

im baffled, by the power of 3, here, how do i find a cartesian equation frmo this, it does give me a suttle hint by saying find x^2/3


Exactly...

x2/3=((cos⁡x)3)2/3=cos⁡2xx^{2/3} = ((\cos x)^3)^{2/3} = \cos^2 x

Same for y2/3=sin⁡2xy^{2/3} = \sin^2 x
Reply 2
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Zacken
22
Original post by Middriver
image.jpg


Full solutions are against forum guidelines.
Original post by Zacken
Full solutions are against forum guidelines.


Oh.
Reply 4
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Zacken
22
Original post by Middriver
Oh.


Have you read this?

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