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Edexcel (IAL) Unit 2 Chemistry June 10th

Hi guys!
So I created this thread for unit 2 chem. Let's revise, share our ideas and clear our doubts here!

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Reply 1
hello
any useful links to study ?


I need a study plan please
Reply 2
Original post by katenell
hello
any useful links to study ?


I need a study plan please


Hey, http://www.chemguide.co.uk is a good website it has alot of resources... I guess your main study plan should be to do past papers and learn from your mistakes, that's what I'm doing anyways
Reply 3
CGP is the number one life saver for anyone!! Like seriously if you don't have it go borrow it, buy it whatever it takes just to read the CGP book (for Edexcel). It includes everything you need to know for the exam and especially helps for last minute revision. :wink:
Reply 4
Original post by wenogk
Hey, http://www.chemguide.co.uk is a good website it has alot of resources... I guess your main study plan should be to do past papers and learn from your mistakes, that's what I'm doing anyways


thanks dude
Reply 5
Original post by I <3 WORK
CGP is the number one life saver for anyone!! Like seriously if you don't have it go borrow it, buy it whatever it takes just to read the CGP book (for Edexcel). It includes everything you need to know for the exam and especially helps for last minute revision. :wink:

what is the cgp ?
the blue book or the pink or what??
Reply 6
Original post by katenell
what is the cgp ?
the blue book or the pink or what??


81zj2U4AtcL._SL1500_.jpg

This is the exact appearance of the book. :smile:
do you think nucleophilic substitution of ammonia is an important topic?
Reply 8
Original post by Hiyoriiki
do you think nucleophilic substitution of ammonia is an important topic?


Yes it is and can be asked this time because the always ask the alcoholic and aqueous KOH qquestion..
Reply 9
Original post by I <3 WORK
81zj2U4AtcL._SL1500_.jpg

This is the exact appearance of the book. :smile:


Where can I get this from? For free?
Reply 10
Original post by wenogk
Yes it is and can be asked this time because the always ask the alcoholic and aqueous KOH qquestion..


Is it required to know the mechanism for this reaction? :redface:
Reply 11
Original post by Sunethra
Where can I get this from? For free?


Well it depends where your location is. Most countries should have the facility of a local library where you may borrow books for free. However a lot of countries don't actually have this facility unfortunately. :frown:
Reply 12
The ion that gives a bleaching property is ClO- or OCl- ? Or are they the same?
Reply 13
Original post by Arzam45
The ion that gives a bleaching property is ClO- or OCl- ? Or are they the same?


Technically they should be the same because the charge applies to the whole compound and not individual atoms. However it is much more preferable and accurate to write it as ClO- because apparently the current chemical formula naming system is according to the alphabetical order of elements. It is called the 'Hill' system for your further information and interest. :smile:
Reply 14
Original post by I <3 WORK
Technically they should be the same because the charge applies to the whole compound and not individual atoms. However it is much more preferable and accurate to write it as ClO- because apparently the current chemical formula naming system is according to the alphabetical order of elements. It is called the 'Hill' system for your further information and interest. :smile:


Thanks a lot mate :wink:
Heyy guys, so i seriously am confused about something. Okay so the thermal stability of group two carbonates and nitrates increases down the group making it more difficult to decompose. I am unsure of the reason for this... It is because

A) at top of group the ions are smaller will a larger charge ( large charge density) and therefore result in a stronger force of attraction between the metal ion and the O2 minus of the carbonate ion thus the energy released when those two come together is great and very exothermic. And it states that for a chemical reaction to occur the erergy released when bonds are formed( when O2 minus amd metal ion meet ) must be greater then the energy required to break bonds. Therefore as a smaller metal ions is more exothermic when it meets a O2minus ion ,less additional energy is required for the reaction to take place at top of group but as you go down more additional energy is required as the reaction is less exothermic.

Or is the reason

B) a smaller metal ion at the top of the group with a large charge density has a greater polarising effect on the carbonate ions electrons thus making the bond weaker and easier to break and hence less engery required at top of group and more at bottom ???

I seriously need help becasue the text book pushes more for the first answer but my teacher for the other ....???? 😱😱😱
Original post by Mimiastc
Heyy guys, so i seriously am confused about something. Okay so the thermal stability of group two carbonates and nitrates increases down the group making it more difficult to decompose. I am unsure of the reason for this... It is because

A) at top of group the ions are smaller will a larger charge ( large charge density) and therefore result in a stronger force of attraction between the metal ion and the O2 minus of the carbonate ion thus the energy released when those two come together is great and very exothermic. And it states that for a chemical reaction to occur the erergy released when bonds are formed( when O2 minus amd metal ion meet ) must be greater then the energy required to break bonds. Therefore as a smaller metal ions is more exothermic when it meets a O2minus ion ,less additional energy is required for the reaction to take place at top of group but as you go down more additional energy is required as the reaction is less exothermic.

Or is the reason

B) a smaller metal ion at the top of the group with a large charge density has a greater polarising effect on the carbonate ions electrons thus making the bond weaker and easier to break and hence less engery required at top of group and more at bottom ???

I seriously need help becasue the text book pushes more for the first answer but my teacher for the other ....???? 😱😱😱


As you go down the group thermal stability increases because the size of the cation increases and the nuclear charge decreases and a result the charge density decreases. This means that the polarizing power decreases down the group with decrease in charge density. As a result the ability of the cation to distort the anion is weak as a result we say that the compunds become more ionic down the group. As a result compounds are more stable thus a large about of energy needs to be supplied to decompose the carbonate or nitrate.
(edited 7 years ago)
Original post by Sunethra
As you go down the group thermal stability increases because the size of the cation increases and the nuclear charge decreases and a result the charge density decreases. This means that the polarizing power decreases down the group with decrease in charge density. As a result the ability of the cation to distort the anion is weak as a result we say that the compunds become more ionic down the group. As a result compounds are more stable thus a large about of energy needs to be supplied to decompose the carbonate or nitrate.


Ahhh okay so more the second one... Thanks so much 👌🏻
Reply 18
I'm really confused about something I've just watched and read. I would like to know, since when can a gas boil? I understand that some gases may be in their liquid state and can therefore boil, but is it ever possible for a gas to boil and how if that is true? :s-smilie:
(edited 7 years ago)
Reply 19
Thanks so much as always! Now that you give me the confirmation that this process is simply impossible to be true, that makes me feel relieved! It was baffling because I literally couldn't find anything online that suggests an explanation even though I saw many other websites which implied that a gas can boil.

What you say makes sense now, because thinking about it, they probably meant to talk about the condensation point of a gas rather than the boiling point (because the temperature would still be the same for both).

So thanks again, much appreciated! :smile:

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