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c2 sequences question

u_n+1=36-(u_n)/3
u_1=12
u_2 = 32
n>=1
the sequence tends to a limit L, find L?
the underscores ( _ ) mean subscript
Reply 1
As n,UnUn+1L n \rightarrow \infty, \text{U}_{n} \rightarrow \text{U}_{n+1} \rightarrow \text{L} .
So just replace all the U_ terms with L and solve for L, which is the limit of the sequence.
Original post by B_9710
As n,UnUn+1L n \rightarrow \infty, \text{U}_{n} \rightarrow \text{U}_{n+1} \rightarrow \text{L} .
So just replace all the U_ terms with L and solve for L, which is the limit of the sequence.

got it now! thanks

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