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CCEA AS Maths C2 Tuesday 31st May

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Original post by Xsk
What the hell was that. :s-smilie:


The 'Evaluate' one? I got -2.


Aw yes thanks, heard a lot of different answers for it.


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Reply 21
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Xsk
4
Original post by caitrionacarson
Aw yes thanks, heard a lot of different answers for it.


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Heard a lot of different answers for every question lmao
Original post by 9clpc9
That paper was terrible. Much harder than last year. Did anyone get that bearings question?


I used the sine rule to get the distance from the start to the oak tree, think I got 292.38
Then used trig to get the shortest distance to the path.
Sin(30)=d/292.38
D= 146.19
~146

Anyone else?


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Reply 23
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9clpc9
2
Original post by caitrionacarson
I used the sine rule to get the distance from the start to the oak tree, think I got 292.38
Then used trig to get the shortest distance to the path.
Sin(30)=d/292.38
D= 146.19
~146

Anyone else?

I used the sine rule too, but I forget my answers.
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For the last question what did everyone get?

Anyone got the papers too?
Reply 24
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lmg1
OP
7
Original post by caitrionacarson
I used the sine rule to get the distance from the start to the oak tree, think I got 292.38
Then used trig to get the shortest distance to the path.
Sin(30)=d/292.38
D= 146.19
~146

Anyone else?


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I Got a similar answer for that but I've only realised that I used the two angles given, should I have found out the missing angle and use it?
Also does anyone have an idea what you would need to get an A or an B on that paper, even in my case a c?
Original post by 9clpc9
For the last question what did everyone get?

Anyone got the papers too?


Think I got (x+3)^2 + (y-2)^2 = 25




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Reply 26
Avatar for lmg1
lmg1
OP
7
Original post by 9clpc9
For the last question what did everyone get?

Anyone got the papers too?


I barely got answers to them questions... I have the question paper to both if that's what you mean.
Reply 27
Avatar for ozmo19
ozmo19
16
Original post by caitrionacarson
Think I got (x+3)^2 + (y-2)^2 = 25

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That is what i got too.

1)a) y=4x-(1\x)+4
b)ii) 4.61
3)a)-19.5,-160 - something like that.
4)i) 242m
ii) 213m
5)i)59.3
ii)130
6)a) -2
b)-1.58
8)b=2
(x+3)^2 + (y-2)^2 = 25
Reply 28
Avatar for 9clpc9
9clpc9
2
Original post by ozmo19
That is what i got too.

1)a) y=4x-(1\x)+4
b)ii) 4.61
3)a)-19.5,-160 - something like that.
4)i) 242m
ii) 213m
5)i)59.3
ii)130
6)a) -2
b)-1.58
8)b=2
(x+3)^2 + (y-2)^2 = 25


I don't remember exactly what I got as my answers but it looks familiar! I got the same for 6b and 8

Original post by lmg1
I barely got answers to them questions... I have the question paper to both if that's what you mean.


Hi, yeah can I get pics of the question paper please?
Reply 29
Avatar for Xsk
Xsk
4
Original post by caitrionacarson
I used the sine rule to get the distance from the start to the oak tree, think I got 292.38
Then used trig to get the shortest distance to the path.
Sin(30)=d/292.38
D= 146.19
~146

Anyone else?


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Sine rule was 200/sin30 = x/sin40, so x = 200sin40/sin30 = 257.12, trig from there?
Reply 30
Avatar for ozmo19
ozmo19
16
Original post by Xsk
Sine rule was 200/sin30 = x/sin40, so x = 200sin40/sin30 = 257.12, trig from there?


This is what I did. I then used sine rule again followed by pythagoras to get 242m
Original post by Xsk
Sine rule was 200/sin30 = x/sin40, so x = 200sin40/sin30 = 257.12, trig from there?


I got that too, and for the shortest distance i got 266 i think
Anoyone have access to the paper?
Reply 33
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Xsk
4
Original post by Smcdonald98
I got that too, and for the shortest distance i got 266 i think

Using trig, the shortest distance = 257.12sin70 = 242?
Original post by Xsk
Sine rule was 200/sin30 = x/sin40, so x = 200sin40/sin30 = 257.12, trig from there?


Aw damn I did x/sin110=200/sin40

Oh well


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Reply 35
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Xsk
4
Original post by ozmo19
This is what I did. I then used sine rule again followed by pythagoras to get 242m

That seems like a longer way of doing it :tongue:
Reply 36
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ozmo19
16
Original post by Xsk
That seems like a longer way of doing it :tongue:


It was the only thing i could think of at the time:tongue:
Reply 37
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Xsk
4
Original post by caitrionacarson
Aw damn I did x/sin110=200/sin40

Oh well


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sin40? If you had done sin30 then you could have done an alternate method, from what I can see :redface: You sure you didn't?
I stored some answers on my calculator:

137, 257, 357, 266, 59.3, 119, -1.58,

324, 256 - my values for n and k
Original post by Xsk
sin40? If you had done sin30 then you could have done an alternate method, from what I can see :redface: You sure you didn't?


Yeah I think I drew the diagram wrong, would need to see the question to see what I done.


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