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Maths help

can you solve this?

The value of x(y-4)/5 is -2
Work out the possible pair of values for x and y

Thank you
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Reply 2
Avatar for Zacken
Zacken
22
Original post by student.feed
can you solve this?

The value of x(y-4)/5 is -2
Work out the possible pair of values for x and y

Thank you


Post the full question.
Original post by Zacken
Post the full question.


That is all. I have attached the paper. It is question 1. Even my maths teacher, didn't know the answer :s-smilie:
RevisionEx.pdf134.5KB
Reply 4
Avatar for Zacken
Zacken
22
Original post by student.feed
That is all. I have attached the paper. It is question 1. Even my maths teacher, didn't know the answer :s-smilie:


Do this:

x(y-4) = -10

Now what two numbers multiply to make -10?

For example, -2 and 5 do, x=-2 and y-4 = 5 means x=-2, y=9 works.

Or x=5, y-4 = -2 works.

Or x=10, y-4 = -1 works.

etc...

You really only need to use one of the above pairs.
Reply 5
Avatar for Med3
Med3
17
x=2 and y=-1
Original post by student.feed
can you solve this?

The value of x(y-4)/5 is -2
Work out the possible pair of values for x and y

Thank you












Then the x's cancel out





So now you know what Y is, you can substitute it into the original equation to get the value of X











x=1
y= -6




BTW, I have no clue if this is right! Correct me if I'm wrong! I was just improvising...
(edited 7 years ago)
Original post by Zacken
Do this:

x(y-4) = -10

Now what two numbers multiply to make -10?

For example, -2 and 5 do, x=-2 and y-4 = 5 means x=-2, y=9 works.

Or x=5, y-4 = -2 works.

Or x=10, y-4 = -1 works.

etc...

You really only need to use one of the above pairs.


Thank you very much
Reply 8
Avatar for Zacken
Zacken
22
Original post by amanii_ox

BTW, I have no clue if this is right! Correct me if I'm wrong! I was just improvising...


It's wrong.
Original post by amanii_ox










Then the x's cancel out





So now you know what Y is, you can substitute it into the original equation to get the value of X











x=1
y= -6




BTW, I have no clue if this is right! Correct me if I'm wrong! I was just improvising...

Thank you :smile:
Reply 10
Avatar for Zacken
Zacken
22
Original post by student.feed
Thank you very much


No worries. By the way, the question in your document is very much different to the question you asked on here.
Original post by SargentZenj2
x=2 and y=-1


Thank you
Original post by SargentZenj2
x=2 and y=-1


Yes that is one of the possible values!!
Original post by Zacken
No worries. By the way, the question in your document is very much different to the question you asked on here.


Oh. Anyways thank you for letting me know
Original post by student.feed
Thank you :smile:


No problem, BTW there are other ways to work it out, there is a range of possible values, this is just one possible value :smile:
Original post by student.feed
Thank you :smile:


FYI this was just plain wrong. Ignore it, just look at Zacken's post.
Original post by IrrationalRoot
FYI this was just plain wrong. Ignore it, just look at Zacken's post.


Yes, I did :smile:
SHOULD'VE LOOKED LIKE THIS SOZ!
5. y = (-10+4x)/ x
Original post by AnIndianGuy
Well step 5 is incorrect. When you divide through by x 10 should also be divided through by x
Original post by student.feed
can you solve this?

The value of x(y-4)/5 is -2
Work out the possible pair of values for x and y

Thank you


x(y-4) = -10
y-4 = -10/x
y = (-10/x + 4)
x(-10/x + 4 - 4) = -10
x(-10x) = -10
-10x^2 + 10 = 0
-10(x^2 - 1) = 0
x^2=1
x=1
y = (-10/1 + 4)
y= -6


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