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Acid to conjugate base ratios

image.jpgWould anyone be able to show me how to do these questions pls?
Original post by AqsaMx
image.jpgWould anyone be able to show me how to do these questions pls?


Your teacher has already shown you in the margin!!!
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AqsaMx
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Original post by charco
Your teacher has already shown you in the margin!!!


I feel like that's what I did though?
Isn't the H+ conc and conc of the conjugate base the same??
(edited 7 years ago)
Original post by AqsaMx
I feel like that's what I did though?
Isn't the H+ conc and conc of the conjugate base the same??


pKa = 4, ka = 1 x 10-4
pH = 3, [H+] = 1 x 10-3

ka = [H+][A-]/[HA]

Hence, the ratio of conjugate base to acid = [A-]/[HA] = ka/[H+] = 1 x 10-4/1 x 10-3 = 1 x 10-1 = 0.1
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AqsaMx
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Original post by charco
pKa = 4, ka = 1 x 10-4
pH = 3, [H+] = 1 x 10-3

ka = [H+][A-]/[HA]

Hence, the ratio of conjugate base to acid = [A-]/[HA] = ka/[H+] = 1 x 10-4/1 x 10-3 = 1 x 10-1 = 0.1


That's the answer I got..

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