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I'm a catfish AMA

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Have you catfished many users on this site? And if so, why do you do it?
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http://www.thestudentroom.co.uk/showthread.php?t=4144183&p=65475757#post65475757
Reply 3
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yasmin123456
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Original post by Mochassassin
Have you catfished many users on this site? And if so, why do you do it?


I don't catfish on here it's only on Facebook and the main reason is because I'm bored
Reply 4
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yasmin123456
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Original post by Plantagenet Crown


hahaha I actually saw this a few minutes before I posted :tongue:
A catfish without a photo of a solid e33\frac{e^3}{3}? :tongue:
Reply 6
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yasmin123456
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Original post by SeanFM
A catfish without a photo of a solid e33\frac{e^3}{3}? :tongue:


I don't catfish on here, I do on Facebook :tongue:
Another AMA?
Original post by yasmin123456
I don't catfish on here, I do on Facebook :tongue:


Have you looked into fishing or tai chi? They sound like fun things to do if you are bored :kungfu:
Reply 9
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yasmin123456
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Original post by ODES_PDES
Another AMA?


Was it that difficult to ignore? :tongue:
Original post by SeanFM
Have you looked into fishing or tai chi? They sound like fun things to do if you are bored :kungfu:


I wouldn't want to go fishing and I've never really thought about doing tai chi before
:afraid:
Original post by SeanFM
A catfish without a photo of a solid e33\frac{e^3}{3}? :tongue:


:lol:

The new standard for catfishes is 4π+eϕ\displaystyle \dfrac{4\pi + e}{\phi} :yep:
has anyone ever found out that you catfished them?
Original post by Indeterminate
:lol:

The new standard for catfishes is 4π+eϕ\displaystyle \dfrac{4\pi + e}{\phi} :yep:


what is that equation meant to be?
Original post by alishba-rosex
has anyone ever found out that you catfished them?


yeah 3 or 4 times
Original post by Indeterminate
:lol:

The new standard for catfishes is 4π+eϕ\displaystyle \dfrac{4\pi + e}{\phi} :yep:


:eek4: that is end of the scale stuff :K: #imperialmathsgoals
nice life
Ugh
Original post by sleepysnooze
nice life


thank you

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