The Student Room Group
Uni students - Complete our survey >>
Uni students - Complete our survey >>
Uni students - Complete our survey >>

C3 graph transformations

I can't seem to upload the picture of the graphs but given that y=f(x) where f(x)=e^x, why does the graph y= 2f(x)-1 still cross the y axis at y=1 and not cross the y axis at y=0? I thought that the graph would be steeper and translated 1 unit down but the mark scheme says otherwise.
Reply 1
Avatar for Zacken
Zacken
22
Original post by _kates23
I can't seem to upload the picture of the graphs but given that y=f(x) where f(x)=e^x, why does the graph y= 2f(x)-1 still cross the y axis at y=1 and not cross the y axis at y=0? I thought that the graph would be steeper and translated 1 unit down but the mark scheme says otherwise.


Yes, but it's stretched by 2 units first. So it originally crosses the y-axis at y=1, then gets stretched to y=2 then moves down to y=1.
Reply 2
Avatar for _kates23
_kates23
OP
Original post by Zacken
Yes, but it's stretched by 2 units first. So it originally crosses the y-axis at y=1, then gets stretched to y=2 then moves down to y=1.


Thank you, it makes sense to me now!
Reply 3
Avatar for Zacken
Zacken
22
Original post by _kates23
Thank you, it makes sense to me now!


Great! :smile:

Quick Reply

Related discussions

Latest

Trending

Trending

Articles for you