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Edexcel AS/A2 Mathematics M1 - 8th June 2016 - Official Thread

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didnt get chance before so thanks Zacken for helping me last time :smile:

. anyways for this question (June 2014 R) for part b) i got that s = 0.3m but the mark scheme says you need to do 0.3 x 2 to get the answer and i don't understand why?

Reply 761

Clovers

Original post by KloppOClock

Thrust is opposite to tension.

Tension:

O---->-------<-----O

Thrust:

O<---->O

Original post by wenogk

Thank you!

This question uses "thrust" check out examsolutions video for that question(Q6)
http://www.examsolutions.net/a-level-maths-papers/Edexcel/Mechanics/Mechanics-M1/2009-June/paper.php#Q6

Ahh right thanks :smile:

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Reply 762

TercioOfParma

Just did the specimen paper, what are the boundaries?

Reply 763

Someboady

Original post by Thomith

didnt get chance before so thanks Zacken for helping me last time :smile:

. anyways for this question (June 2014 R) for part b) i got that s = 0.3m but the mark scheme says you need to do 0.3 x 2 to get the answer and i don't understand why?

The particle returns to the point where the tension is lost. So it will travel back the same distance hence x 2.

Reply 764

Marxist

Original post by AlphaArgonian

Can someone explain Q7 to me, please?

https://drive.google.com/file/d/0B1ZiqBksUHNYS180T0M2V1FZTnM/view

Arsey's way is superior imo, but hope this helps. For some guy.jpeg

Reply 765

Dinaa

Original post by AlphaArgonian

Can someone explain Q7 to me, please?

https://drive.google.com/file/d/0B1ZiqBksUHNYS180T0M2V1FZTnM/view

I used (v-u)/t = acceleration
So : 2i+9j – (-3i-3j) divided by t
= (5i + 12j)/t

Gives us the magnitude therefore:
(5/t)^2 + (12/t)^2 = 2.6^2
= 25/(t^2) + 144/(t^2) = 6.76

Multiply all my t^2 to get 169=6.76t^2
SoT= 5

Sub this into the first part (5i +12j)/5 = 1 and 2.4 

Reply 766

Dinaa

Original post by Marxist

Arsey's way is superior imo, but hope this helps. For some guy.jpeg

Got there before me :wink:

My method is a tad different tho, shocked I got it right tbh haha. :colondollar:

Reply 767

Dinaa

Original post by Louiseelg0rt

When a vector is A relative to B, is that the same as the vector BA? or is it the vector AB?

A relative to B is BA

Reply 768

thelegend99

Anyone found any *really* hard questions that come up?

And I just can't get my head around "what does inextensible show/how have you used that in your calculation" kinda questions.

Reply 769

Don Pedro K.

Original post by thelegend99

Anyone found any *really* hard questions that come up?

And I just can't get my head around "what does inextensible show/how have you used that in your calculation" kinda questions.

inextinsible string means that acceleration of both particles attached will be the same :smile:

Reply 770

Don Pedro K.

Original post by thelegend99

Anyone found any *really* hard questions that come up?

And I just can't get my head around "what does inextensible show/how have you used that in your calculation" kinda questions.

This is because as soon as one particle moves, the other one moves with it since the string can't stretch!

Reply 771

thesuperdark

For vectors, does it matter whether we write them in i + j form, or the other form with the brackets (forgot their name!)?

Reply 772

amelienine

How do we use the information that the string is light?

Also, for questions where the string breaks, that would mean that the tension in the string is now 0 and so we would have to find the new acceleration for the particle, right?