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Edexcel AS/A2 Mathematics M1 - 8th June 2016 - Official Thread

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I would have thought that saying 135 or 45 from horizontal are both wrong if there is no clockwise/anti-clockwise mentioned. I wrote 45 degrees from horizontal-south west then added bearing of 225
Posted from TSR Mobile thats fine then youll get the marks

Reply 1161

username1625799

Original post by HasanRaza1

grade boundary predictions?

Probably like 55-60 for an A depends, how did your class find it?

Reply 1162

Mizzeeboy

What did people get for the moments question?
I got d=3.2 and M = 162
(BTW I'm not saying its right)

Reply 1163

Questioner1234

Original post by CaiusMartius

Taken from an almost identical question from June 2013.

"Direction clearly marked on a diagram, with an arrow, and 45o (oe)marked"

Oh OK with a diagram That would be fine but I'm saying if you just wrote 45 from horizontal or just wrote 135 from horizontal with no diagram in close proximity then they have no idea whether it's north west/south west/north east/south east. But yes that's great then I just hope I remembered to label my diagram...

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Reply 1164

jshark97

Original post by xz6

Anyone else get bearing 225deg for direction??

Yes, resultant force of 16.6 N on a bearing of 225 degrees is what I got

Reply 1165

Questioner1234

Original post by student bang

What was the coefficient of friction, I got 0.873

Got 0.727

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Reply 1166

Reda2

And guys I have a very important question this is what I will either get me a nearly full UMS or complete fail. I did the graph IN PENCIL and I forgot I was using pencil and just carried on with the paper! Realising it on the last question, this won't lose me marks right??? I even wrote on the pages I used pencil "Sorry I forgot I was using pencil" !! anyone please??

Reply 1167

alexesl17

Original post by xz11

I think you will find its the same as 135deg from the horizontal not 45

its 135 from the vertical

Reply 1168

hamzahussain97

Original post by Reda2

Guys for the direction of the force on the pulley, it's not in terms of bearings, look at this past paper, you had to draw on the diagram.

Question: http://www.mediafire.com/convkey/8466/fpk2xkpxefvfrrezg.jpg
Mark scheme: http://www.mediafire.com/convkey/aa8b/trt8g28hmc664c7zg.jpg

If that's the case I think i got the marks.

Reply 1169

Mizzeeboy

Original post by student bang

What was the coefficient of friction, I got 0.873

I got 0.727 I think

Reply 1170

dj3k

Original post by Formless

^^^ This is 100% correct, Any idea the marks for the impulse questions

Doesn't R have to be 15.5N to 3sf or 16N to 2sf, not 15.45?

Reply 1171

Maxsmith797

Original post by student bang

What was the coefficient of friction, I got 0.873

im pretty sure it was 0.727

Reply 1172

OrionMusicNet

Original post by Mizzeeboy

What did people get for the moments question?
I got d=3.2 and M = 162
(BTW I'm not saying its right)

d=1.2 M = 48

Reply 1173

dj3k

Original post by Mizzeeboy

I got 0.727 I think

Yeah I think I remember getting 0.73 to 2 dp.

Reply 1174

hogree

Just a shout, for 2b, it was definitely 14.7? Quite confusing phrasing.

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Reply 1175

student bang

What was the coefficient of friction, I got 0.873??

Reply 1176

Jellymath

Fairly easy test this time around. Here are my answers which should be correct:

1. 104 degrees, 640i+640j
2. T=20.6N , R=15.5N
3. Impulse = 3Ns
4. Graph with one point of intersection, T = 8.75s
5. Moments qn: d=1.2m M=42kg
6. Coefficient of friction = 0.727
7. 2.5i+2.5j, 13 ms-1
8. T=11.8N, F=16.6N bearing 225 degrees

Reply 1177

hello11223344

I swear for question to the weight was in kg and the acceleration was in ms-2 therefore the answer was R=15450
as you have to convert the masses into grams

Reply 1178

ShatnersBassoon

Original post by CaiusMartius

Taken from an almost identical question from June 2013.

"Direction clearly marked on a diagram, with an arrow, and 45o (oe)marked"

I knew I remembered a similar question, but I couldn't remember what form they wanted. Did that mark scheme accept other forms?

I ended up writing four answers for the direction (or at least, the same answer in four different ways). I had a diagram of the pulley with the string's tension acting on it, an arrow for the resultant force (labelled "resultant force") and North marked on it (directly upwards). I then wrote four answers: "bearing of 225 degrees", "due southwest", drew an arrow in the right direction and "with direction vector -i-j". There is no way they can reasonably not give me the mark.