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OCR (Not MEI) S1 Wednesday 8th June 2016

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Original post by bowders
Also did anyone get 146.5 for the mean of the apples?


yes
What points did everyone plot for the 2 marks in spearmans rank (where rs = 1 but r does not equal 1)
Reply 162
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Ozil5
8
Original post by sen99
oh **** yeah sorry it was spearmans rank


Haha no worries, you had to use their position on the x and y axis as ranks, so they were 12345 and 12354. I think the final answer was 0.9
Reply 163
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Ozil5
8
Original post by Breynolds2671999
What points did everyone plot for the 2 marks in spearmans rank (where rs = 1 but r does not equal 1)


Did a straight line with one point higher than the rest
Original post by Breynolds2671999
I thought it was that < 130 < or equal to 140 (or something like that)
At 140 it is the LQ. At the LQ there is 25%.

100% is 52 apples so 25% is 13.

Thanks! That makes sense
Original post by Ella rivers1
Yeah I did like probability of x greater than or equal to 2 for n as 3 and p as 0.3


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Did you have to do it that way? I think I just used the probabilities in the table to do it
Original post by h3rmit
I got 0.04, but 0.072 for the second one

I got 0.04 and 0.072 as well
Original post by Breynolds2671999
What points did everyone plot for the 2 marks in spearmans rank (where rs = 1 but r does not equal 1)


I did it so that the points created a curved line
Reply 168
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madberry1
OP
1
Original post by liverpool7867
For the 'abba' question:

I think it was ((3C2 x 2C2) x (2! x 2!))/ 7C4 x 4! = 1/70

I think that was correct


Yeah that's what I did cause you had to pick 4 from 7 but then there were 4! Ways of arranging that 4 then finding the arrangements of ABBA and just dividing
Reply 169
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Ab9009
Original post by swagmister
I did it do that the points created a curved line

It doesn't matter as long as the ranks were equal and it wasn't a straight line
Original post by cc262626
Are you sure?! Loads at my school said was wrong


It is right, I did it a weird way, but there were three ways of picking two As and two Bs, so I did 3/7C4 which was 3/35, but then out of the two As and the two Bs, there are 6 ways of arranging them so there's a 1 in 6 chance of it being in the order of ABBA. So I divided 3/35 by 6 which is 1/70, or 0.0143
Original post by swagmister
I did it so that the points created a curved line


I did the same :biggrin:
Original post by Breynolds2671999
What points did everyone plot for the 2 marks in spearmans rank (where rs = 1 but r does not equal 1)


a curve
can we make a markscheme? on here or a goole docs? just so we can see it all laid out
Original post by Breynolds2671999
What points did everyone plot for the 2 marks in spearmans rank (where rs = 1 but r does not equal 1)


A zigzag which has a positive correlation, means r not 1 but rs still=1
Let's do another community MS. Please press the button to request permission to contribute.
https://docs.google.com/document/d/1uL5DuXry9Kc-sc2DE1QXz7e2FqW9JsV0TmVhI79VAGI/edit?usp=sharing
wat was the second past of question 1?
How did you work out mean of z?
45 marks for an A.
Original post by Btec certified
45 marks for an A.


I wish :biggrin:, probably about 56 or 57

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