Edexcel FP2 Official 2016 Exam Thread - 8th June 2016

I know it wasn't

I found the same in the differential equation. Is that sth in polar -9/4rt(3) ?
What radius and centre did you also get in the transformation question?

That isn't the same thing. Yes it's ibp twice, but it's obviously integration by parts twice as you can easily see how by doing by parts you are going to get to a point where you get an integral independent of x - this isn't the case for e^2x sinx as most people get taught that you can't use IBP for things like sine that go round in circles, so you might do it once and then you get to a very similar point and probably stop. You can say all you like about it but when all but 2 people at a grammar school, many of whom will go to top unis and get very high grades, can't do the question it suggests that it isn't just a normal question that people are stupid for not getting right. We get it, you do step but not everyone does.

Damn I practiced so many complex transformation questions and then it didn't come up! Really struggled for time towards the end but looking at these answers does inspire some confidence.

I probably spent the longest doing the integral in question 4(b), I couldn't figure out a better way to do it so I used FP3…

The integral seems right according to wolfram alpha, yet when I differentiate the whole thing I don't get dy/dx = 0 when y = 0 and theta = 0, so I probably did it wrong

Answers - let me know if they need to be edited (edit - typo on 5 fixed)
1) -2<x<-root2 -1<x<root2
2) shown x(x^2-3x-9)/2(x+2)
3)e^ipi(1/24, 13/14, -11/24, -23/24) shown
4) r/q(1-e^-(q/p)t) (2sinx-cosx+e^-2)/5
5) Coefficients are 1/16, -5/16, 10/16 shown
6) coefficients are 1 2 2 8/3 then shown
7) Ax^2+Bx-1/12x^(-2)
8) 21/4, (+-)arcos(3/4) 32.519 which I think was 3root7/4-11arcos3/4+49pi/4
Hope this helps everyone!

Did anyone get this for 4(c):

You haven't divided your constant by e^2theta

umm centre (-5/8,0) radius = 7/8,

i think its not -9/4 rt3, its more complicated , like some two digits numbers. , what I'm sure is that i have calculated the answer in calculator and it is value is 0.5xxx

Anyone know the anwer for 7 and 8?

Oh crap. That's the A1 down the drain

no part c

there was part ai and aii

and part b



anything so long as you have FP1 and FP2 or FP3

And in maths you must have S1+S2, D1 + D2, M1 + M2, or 2 of D1, M1 and S1. So you can't have M1, D1 and S1 in FM

Nah,
5. De Moivres (5M) + (5M)
6. Tan(x) (5M) + (5M)
7. Second Order Diff (4M) +(7M) + (2M)
8. Polar Coordinates (3M)+ (8M)

okay so based on what you're saying could you have the following as a possible arrangement?

math: c1-4, d1, m2
further: fp1-2, m1, s1-3

Ax^2+Bx-1/(12x^2)
21/4, arcos(3/4)
21/4, -arcos(3/4)
32.5, or 49pi/4+3sqrt7/4-11arcos3/4