Edexcel AS/A2 Mathematics M1 - 8th June 2016 - Official Thread

I thought it was because the front cover looked like this (from previous IAL paper):


A standard paper looks like this:



I mean I could be wrong of course. That's my reasoning.

What even is an IAL paper? The international papers?



Oh i guess that'd be fine. Although oads of people in my class literally just wrote 45 degrees from the horizontal then laughed cause I was the only one who got a bearing.

I initially accepted that i was wrong but upon giving it further thought, I think they messed up.

In the exam it looks like that so you cant see straight away how many questions there are in the paper. Besides this is standard edexcel layout

Could someone explain to me why the force exerted by the brick is 15.45N and not just its weight, 14.7N. I understand it's accelerating upwards and so there must be a net upwards force greater than the weight. The difference between the force and the weight is the force required to make it accelerate at 0.5m/s^2, so net upwards =1.5g + 0.5x1.5=15.45. Surely though, this is the force that the pan exerts on the brick and not what the brick exerts on the pan? Or am I correct and have I just messed up when reading the question and it's actually asked me to find the force of the pan on the brick?

Also for 7. Is F2 = 2.5i+2.5j or -3.5i+-3.5j. The two answers are pending on which way you put the ratio to find your answer ie 3(-1+x)=2+x and -1+x=3(2+x). Which one is right? I put the 2.5 one but I now think -3.5 was right. How many marks would I lose if it's wrong?

Lastly, for the diagram, I did something stupid. I drew all of it correctly (so correct height/speed, time they decelerated and time stopped) except I didn't make their lines intersect when they were decelerating. Meaning M was above N for the entirety of the graph except for the stop point. Thus meaning they traveled different distances, which we know is wrong. Do I just lose one mark?

I'm beginning to think the only answer they'll accept for the last question is 225 as a bearing.

Saying 45 doesn't make sense. It's not specific enough. Your force could be going south east or south west.

Only giving your answer as a bearing leaves no uncertainty to the examiner

guys, will I lose marks if I wrote 11.76N instead of 12/11.8 N for 8A ?

guys, will I lose marks if I wrote 11.76N instead of 12/11.8 N for 8A ?

I remember from last year the layout was like that of the 2nd picture. Mainly becasue my friend missed out 2 whole questions in C2 and we were telling him that it even said at the front how many questions there was.

I don't remember the paper that well but I think this is what I got

$F_1=-i+2j$ and let $F_2=\lambda (i+j)$

then $F_{resultant} = F_1+F_2= (-1+\lambda)i+(2+\lambda)j$

since we know that the resultant force is in the direction of $i+3j$

$3(-1+\lambda)=(2+\lambda)[br]\Rightarrow \lambda =2.5[br]\Rightarrow F_2=2.5i+2.5j[br]\Rightarrow F_{resultant}=1.5(i+3j)$

Also for the last question it asked for the direction of the force exerted on the pulley. So if your taking the pulley as the origin and the north being upwards perpendicular to the table, then the bearing would be 225. But if you drew the diagram with arrows and angles, you'll probably still get it. Your other answers look familiar but I can't really say a mark with certainty - maybe mid 60s depending on that moments q.

I really messed up on question 7....

I had no idea what to do.

Could someone post the solution to 7b?

They just standardised their front covers to what it is for every other Pearson/edexcel exam. Basically all the GCSEs and other A-level papers look like this. We sat a UK paper today.

does anybody know how many marks the moments question was altogether?

7b told you the acceleration and the velocity of P at t=0. Can't remember the values. Acceleration is rate of change of velocity or in other words delta v/delta t = a. So you find delta v byt multiplying the acc. by 3 (3 = delta t). That value is the amount the velocity of P changed by from t=0 to t=3. So you add the starting velocity and the change in velocity. That gives you the velocity at t=3. Then you use pythagoras to find the speed and there you have it. Hope that makes sense.

does anybody know how many marks the moments question was altogether?