2016 Unofficial M1 Mark Scheme? 2016

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Reply 120

Maim56

How many marks was 8b

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Reply 121

sakuraton

How marks do I get if I got RS=0 and RT=0 the wrong way round but still got d and M, even the d and M is wrong?

(edited 7 years ago)

Reply 122

RattyApple

Original post by philo-jitsu

For people who got d=1.6 and m=66 because of using wrong distance....if we showed all working how many marks would we get out of the 7?

Also i drew the graph correct except the 30ms graph decelrated before the 40ms line so the area was less/wrong....how many out of 4 if everything else was correct?

Also for some reason i think i got exactly double th etension in q8....i used the correct method for part b...do i get ecf?

Thanks for anyone who can help

I got 66 too :frown:

Reply 123

jordan_chung18

Original post by KINGYusuf

Isn't the last Q:

resultant force = 2Tcos45? So around 8. something

See that's what I got but I got the tension as 0.8g (7.84N) so I got something like 11.09 -->11.1N

Reply 124

kapisz

can someone show q7 a working out?

and if u got d=1.6 and M=66 due to using wrong distance but working correct how many marks would i get?

Reply 125

Haamoo7

Original post by ak33m98

Are you sure that for question 5, μ was to 2 significant figures and that 8b asked for the angle?

They didnt ask for a specific sig fig for question 5, so μ could probably be to 1, 2 or 3 sig fig (based on previous years markschemes).

And yeah, 8b asked for the magnitude and direction. So essentially an angle/bearing was required.

Reply 126

Lucas.Kaiser

Original post by Haamoo7

R - 1.5g = 1.5a
Since a was 0.5ms-2,

R - (1.5x9.8) = (1.5x0.5)
R - 14.7 = 0.75
So R = 14.7 + 0.75 = 15.45

I got 5.15N because there was tension as well:

T - R - (1.5x9.8) = (1.5x0.5)
R = 20.6 - 14.7 - 0.75
So R = 5.15N

Reply 127

awiodnaio

Can anyone tell me the mass of the scale pan and the brick inside it respectivley?

Reply 128

don't cry-craft

For 1c) I got unto t=32, but then i got the wrong position vector (I probs subbed the 32 into the wrong equation). How many marks would I lose?

Reply 129

Haamoo7

Original post by Lucas.Kaiser

I got 5.15N because there was tension as well:

T - R - (1.5x9.8) = (1.5x0.5)
R = 20.6 - 14.7 - 0.75
So R = 5.15N

You don't include tension when just looking at the brick on the pan.

https://youtu.be/0dDtHonctTg?t=6m55s

You only include tension when looking at the lift as a whole system (e.g. the first scenario of the 2nd column in the video).

Reply 130

Lucas.Kaiser

Original post by awiodnaio

Can anyone tell me the mass of the scale pan and the brick inside it respectivley?

1.5kg for the scale pan and 0.5kg for the brick

Reply 131

Haamoo7

Original post by awiodnaio

Can anyone tell me the mass of the scale pan and the brick inside it respectivley?

Scale pan: 0.5kg
Brick: 1.5kg

(If I remember correctly)

Reply 132

Lucas.Kaiser

Original post by Haamoo7

But if you were just looking at the brick in the pan:

R - 0.5g = 0.5x0.5
R = 4.9 + 0.25
R= 5.15N

Reply 133

Haamoo7

Original post by Lucas.Kaiser

But if you were just looking at the brick in the pan:

R - 0.5g = 0.5x0.5
R = 4.9 + 0.25
R= 5.15N

I remember the brick having a mass of 1.5kg
:/
But yeah if the brick was 0.5kg, you're right.

Reply 134

Lucas.Kaiser

Original post by Haamoo7

Actually I think I got the masses the wrong way around, sorry

Reply 135

peanutbutterjam

If I used the correct method but my numbers were wrong, would I still get the method mark?

Reply 136

tallulabellm

Hey guys also for 1(b) p = (400+15t)i + (20t)j
q = (20t)i + (800-5t)j

I wrote p = 400i + t(20j+15i)
and for q = 800j + t(20i-5t)

I saw in mark schemes this is sometimes how they write it, it means exact same thing, do you think I will get full marks for this?