The Student Room Group

2016 Unofficial M1 Mark Scheme? 2016

Scroll to see replies

Original post by awiodnaio
Hi thanks for the replies Klopp can you please do the scale pan question


I'm trying to do model answers for the questions but I can't find the details of the questions. If you can remember what the question details were then sure.
Original post by KloppOClock
does anyone remember the details of question 6 such as distances and masses?


Yes:
A non-uniform rod AB has a length of 6m and a mass of 30 kg. It is supported by 2 pivots (or was it 2 strings?) at points S and T, where the distance AS = 0.5m and TB = 2m. When a particle of mass M is attached to the rod at A, the rod is about to tilt about S. When the particle of mass M is moved to B, the rod is about to tilt about T.

Assume the distance between A and the centre of mass is d.
Find:
i) the distance d.
ii) the mass M.

Could someone work out the full solution to Q5 (the one with the coefficient of friction). I vaguely remember I might have said .73 but am not sure anymore and when I tried to reproduce it, I got a totally different value (.37), most likely because I can't remember the numbers correctly.

Thank you,
Diana
Original post by hadtosignup
Yes:
A non-uniform rod AB has a length of 6m and a mass of 30 kg. It is supported by 2 pivots (or was it 2 strings?) at points S and T, where the distance AS = 0.5m and TB = 2m. When a particle of mass M is attached to the rod at A, the rod is about to tilt about S. When the particle of mass M is moved to B, the rod is about to tilt about T.

Assume the distance between A and the centre of mass is d.
Find:
i) the distance d.
ii) the mass M.

Could someone work out the full solution to Q5 (the one with the coefficient of friction). I vaguely remember I might have said .73 but am not sure anymore and when I tried to reproduce it, I got a totally different value (.37), most likely because I can't remember the numbers correctly.

Thank you,
Diana


if you post question 5 i will do it after ive done 6
Original post by KloppOClock
does anyone remember the details of question 6 such as distances and masses?


I think it was A-B 6m long,
AS = 0.5 m
TB = 2 m
Original post by hadtosignup
Yes:
A non-uniform rod AB has a length of 6m and a mass of 30 kg. It is supported by 2 pivots (or was it 2 strings?) at points S and T, where the distance AS = 0.5m and TB = 2m. When a particle of mass M is attached to the rod at A, the rod is about to tilt about S. When the particle of mass M is moved to B, the rod is about to tilt about T.

Assume the distance between A and the centre of mass is d.
Find:
i) the distance d.
ii) the mass M.

Could someone work out the full solution to Q5 (the one with the coefficient of friction). I vaguely remember I might have said .73 but am not sure anymore and when I tried to reproduce it, I got a totally different value (.37), most likely because I can't remember the numbers correctly.

Thank you,
Diana



For the SCALE PAN question:
A scale pan of mass 0.5 kg is attached to a string. In the scale pan there is a brick of mass 1.5 kg. The scale pan moves upwards with constant acceleration of 0.5 ms^-2. Find:
a) The tension in the string.
b) The magnitude of the force exerted by the pan scale on the brick (or perhaps the other way around, but it doesn't matter cos they're equal).
75/75

as usual...
for the coefficient question i read 40 as 4 and got my final answer wrong but my method was correct.. would i get any marks?... biggest flop
Original post by hadtosignup
For the SCALE PAN question:
A scale pan of mass 0.5 kg is attached to a string. In the scale pan there is a brick of mass 1.5 kg. The scale pan moves upwards with constant acceleration of 0.5 ms^-2. Find:
a) The tension in the string.
b) The magnitude of the force exerted by the pan scale on the brick (or perhaps the other way around, but it doesn't matter cos they're equal).


It was on the scale pan by the brick
Original post by KloppOClock
if you post question 5 i will do it after ive done 6


Hi, Thanks a lot, but my problem is remembering the values in the question. I can't remember the value of the force and the angles of the plane and force... :/
Original post by hadtosignup
Hi, Thanks a lot, but my problem is remembering the values in the question. I can't remember the value of the force and the angles of the plane and force... :/


if you remember as much as you can i can work backwards

i need to know the value of the force acting on the particle, the mass of the particle, and which angle goes where (20 at bottom, 30 on top or 20 at top, 30 at bottom)
(edited 7 years ago)
Original post by KloppOClock
if you remember as much as you can i can work backwards

i need to know the value of the force acting on the particle, the mass of the particle, and which angle goes where (20 at bottom, 30 on top or 20 at top, 30 at bottom)


Here's what I remember:

A particle P, of mass 2kg, is at rest on a rough inclined plane which makes an angle of 20 degree with the horizontal. It is supported by a force of 40N, which makes an angle of 30 degrees with the line of greatest slope of the plane. The particle is in equilibrium and is about to slide up the plane. The coefficient of friction is u. Find the coefficient of friction.

What I am not sure is whether the values for the mass, angles and force are correct.

I wrote F - uR (where R = normal reaction)
Then:
(Perpendicular to plane): R = 2gcos(20) + 40sin(30)
(Up the plane): 40cos(30) - 2gsin(20) - F = 0
=> F = 40cos(30) - 2gsin(20)

u = F / R.

But if I insert the numbers I gave you above, I don't get .73... so I must be mis-remembering something... or I did it wrong.

Maybe someone else remembers the values given?
Original post by hadtosignup
Here's what I remember:

A particle P, of mass 2kg, is at rest on a rough inclined plane which makes an angle of 20 degree with the horizontal. It is supported by a force of 40N, which makes an angle of 30 degrees with the line of greatest slope of the plane. The particle is in equilibrium and is about to slide up the plane. The coefficient of friction is u. Find the coefficient of friction.

What I am not sure is whether the values for the mass, angles and force are correct.

I wrote F - uR (where R = normal reaction)
Then:
(Perpendicular to plane): R = 2gcos(20) + 40sin(30)
(Up the plane): 40cos(30) - 2gsin(20) - F = 0
=> F = 40cos(30) - 2gsin(20)

u = F / R.

But if I insert the numbers I gave you above, I don't get .73... so I must be mis-remembering something... or I did it wrong.

Maybe someone else remembers the values given?


ive uploaded model answer to question 5 under the model answer spoiler
could someone state the method for question 2 part b, thank you
Hey guys also for 1(b) p = (400+15t)i + (20t)j
q = (20t)i + (800-5t)j

I wrote p = 400i + t(20j+15i)
and for q = 800j + t(20i-5t)

I saw in mark schemes this is sometimes how they write it, it means exact same thing, do you think I will get full marks for this?
for question 2 part b, i got 5.15N because the question was about the force on the scale pan, so i thought it would be:
R-0.5g = 0.5 X 0.5
which would give you 5.15 N
im not sure though im slightly confused :/
Original post by Assmaster2
Hey guys also for 1(b) p = (400+15t)i + (20t)j
q = (20t)i + (800-5t)j

I wrote p = 400i + t(20j+15i)
and for q = 800j + t(20i-5t)

I saw in mark schemes this is sometimes how they write it, it means exact same thing, do you think I will get full marks for this?


yeah that's fine you'll get full marks but could you help me with question 2 part b please? stating the method ty.
Original post by KloppOClock
ive uploaded model answer to question 5 under the model answer spoiler


Thank you so much, I really appreciate it! Seeing the full value of u I remember that's what I got - phew! And is seems the solution we have is the same :smile:.

Many thanks for making my day,
Diana
what was question 2?
Original post by twigface
what was question 2?


the one with the tension and scale pan along with a brick

Quick Reply

Latest

Trending

Trending