2016 Official AQA New Spec AS Level Physics Paper 2 - 9th June 2016

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the percision is just the smallest measurement an instrument can do, e.g. a ruler goes up in 1mm increments so the percision is 1mm and the u.c. of a ruler is plus or minus 1mm.

assuming the ruer has mm marks on it of course

I'm so confused do we use half the increment or the smallest increment itself

Reply 81

Someboady

Original post by JackSpinner1

For Q31 - you would redraw the circuit from p to Q to see the differnet path where the current would go. This would cause the circuit to split at the first junction, where one route will go through 4R then directly to Q, and the other path would go to R. After this point (following the path from R) it will split again to a 3R and 6R route and then meet up again, just befote the final R resistor then going back to Q.

You should have have the 3R and 6R resistor in parallel, and so you add them together using 1/Rt = 1/R1 +1/R2 and you will get 2R. This 2R should be in series to the two R resistors, so you add them together to get 4R. Finally this 4R resistor is in parallel to to the other 4R resistor (wich goes directly to Q) and so you add these together and you should get 2R

How do you know to do this? :/

Reply 82

M1key_007

Anyone know of a YouTube video that goes through the specimen set 2 paper 2 (v1.2)? Most of the questions on there don't make sense and the mark scheme is so bad at explaining how to get the answer. I am pretty sure I have already failed the paper tomorrow unless a Miracle~ will happen or the grade boundaries are super low. Any help would be appreciated. Thank you.

Reply 83

BrambleGB

Original post by 11234

I'm so confused do we use half the increment or the smallest increment itself

You would use half of the increment on a ruler but on each side,
so you get 2x 0.5mm which adds up to +-1mm
On digital scales its +-0.5 of the smallest value it can record, but rounded up to 1. So I think you use the non rounded value in any calculations?

Taken from the aqa workbook for the new spec

(edited 7 years ago)

Reply 84

Zeed.

Guys, what other topics do you think will come up so far I'm guessing moments and refraction or TIR?

Reply 85

username2250433

based off paper 1, what topics are more likely to come up on this paper?

Reply 86

runningcat

My teacher didn't explain error bars, please could someone?

Reply 87

username2250433

what is the stopping potential equation? Ive googled it but it came up with dodgy symbols that i havent seen before

Reply 88

BrambleGB

Original post by runningcat

My teacher didn't explain error bars, please could someone?

You just plot the uncertainties onto the graph as a line.

Eg if its +-1mm you add that onto the value

Usually done though with multiple measurements so you end up with a mean, and the error bar is half the range

If asked to calculate uncertainty in gradient, you draw either the line that goes through all the highest or lowest points of the error bars and then find the difference between that and the line of best fit

Reply 89

username2488725

Original post by BrambleGB

You just plot the uncertainties onto the graph as a line.

Eg if its +-1mm you add that onto the value

Usually done though with multiple measurements so you end up with a mean, and the error bar is half the range

Does the latter bullet point mean that on EACH side of the point it is equal to half the range? I.e. the entire bar both UP and DOWN are the entire range?

Reply 90

runningcat

Original post by BrambleGB

You just plot the uncertainties onto the graph as a line.

Eg if its +-1mm you add that onto the value

Usually done though with multiple measurements so you end up with a mean, and the error bar is half the range

Thank you so much! :smile:

Reply 91

BrambleGB

Original post by CrazyFool229

Does the latter bullet point mean that on EACH side of the point it is equal to half the range? I.e. the entire bar both UP and DOWN are the entire range?

Yes, each side of the mean would be half the range.

Reply 92

username2488725

Original post by BrambleGB

Yes, each side of the mean would be half the range.

Cheers! Good luck btw

Reply 93

jessyjellytot14

Original post by M1key_007

Saammmeee

Unfortunately, there aren't any Youtube videos on the set 2 specimen paper that I know of, but there's a channel called ' LAE Physics ' which I find quite helpful and he goes through some of the practical skills that used to be tested in coursework but are now tested in this evil exam.

For example, heres a video he did on calculating uncertainties ---> https://www.youtube.com/watch?v=zrGSDHSOM5E

Reply 94

revise_or_fail

Original post by JackSpinner1

Can someone explain the answer to question 33 on the second set of specimen papers?

Ok so basically the answer can't be C or D because they would give the same voltage. It can't be B because in parallel voltage is same as cell on every branch and so the only option left is A.You could also replace in a voltage for the cell like 12V and as it goes through each resistor it loses 4 volts so 8 volts at Q at 8 at U so potential difference is zero. Answer = A

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Reply 95

BrambleGB

Original post by not_lucas1

what is the stopping potential equation? Ive googled it but it came up with dodgy symbols that i havent seen before

It is the voltage required to bring a electron at Max kinetic energy to a stop.
Where eVs = Ekmax
But seeing as the energy required to stop it is equal to the energy it contains, the stopping potential is simply the maximum kinetic energy of a electron converted to eV(You quote just the V value without e I think, eg 5V not 5eV), because 1 electron needs 1 eV to move through a potential difference of 1V.