AQA AS Physics Unit 2 (PHYA2) June 9th 2016 Resit paper

kinda, basically if you resolve horizontally in this "theory" without air resistance there is no resistive forces to decelerate(slow it down) and it will not be accelerating as there is no thrust proving acceleration(no overall force as no acceleration so only v=s/t applies)so we use the impulse velocity, which is what it is travelling as it left the racket and as the time of horizontal and vertical displacement is the same/constant (read about monkey-hunter model) we can use v=s/t so v is proportional to s (as t is constant).so basically all values are max

When air resistance occurs in practice horizontally: the time to displace horizontally and vertically is still the same(constant) however there is a resistive drag force on the ball which causes it to decelerate, as there is no thrust on the ball after it has left the racket the only horizontal force acting on it is the air resistance which will be large and slowly decrease(decelerate the ball) until zero when it no longer moves horizontally So as the ball is decelerating its mean velocity is less. so v=s/t (where t is constant) if v decreases, t is constant then s must decrease

not much, done like 6 of the papers and i do maths mechanics which helpsish

Thanks I understand, so then why does it matter if u use 3m or 50m for distance?

He hasnt travelled 3M, ...think in triangles, 50m is the resultant distance. so the 50m is already accounting for the 3m. it accounts for the horizontal distance and the 3m vertically

not much, done like 6 of the papers and i do maths mechanics which helpsish

So u think they can't ask much different from past papers? Worried they might ask something not seen on a past paper and I'll fail it

Howd you find M1.....mine did not go great....lots of really dumb errors....the only redeeming quality is that I made so many dumb errors I think I'm all out for the rest of the exams.....its plain sailing from here on in .... :-)

I will try to remember as many questions as possible tomorrow....hopefully we can formulate an unofficial mark scheme....physics answers are relatively straight forward so it should be doable

ahah same man m1 was messy this year :/ i made so many stupid small mistakes but my biggest were on the impulse question i got everything (method right) but i got the deceleration wrong cos i forgot to divide by 0.4 such a rookie error aha hopefully will only lose 2 marks max cos it it, also the 7a) vectors i couldn't finish off so lost almost all the marks on that question. You doing c3/c4?

Yeah, oddly enough im way more confident about them...and yeah I did the opposite, I got the impulse and simultaneous equation vector equation, but I messed up the speed time graph question, and the last question I did the first equation right but for the vertical side of the pulley I put T as positive instead of negative......so many ways to mess up on M1....its infuriating

and I messed up the moments question, and I got the wrong distance...used 6m instead of 4m....such a dumb mistake!!

pretty much need 95ums in both c3&4....so no pressure!!

Yeah, oddly enough im way more confident about them...and yeah I did the opposite, I got the impulse and simultaneous equation vector equation, but I messed up the speed time graph question, and the last question I did the first equation right but for the vertical side of the pulley I put T as positive instead of negative......so many ways to mess up on M1....its infuriating

and I messed up the moments question, and I got the wrong distance...used 6m instead of 4m....such a dumb mistake!!

pretty much need 95ums in both c3&4....so no pressure!!

Howd you find M1.....mine did not go great....lots of really dumb errors....the only redeeming quality is that I made so many dumb errors I think I'm all out for the rest of the exams.....its plain sailing from here on in .... :-)

How do you do q.4 (c)(i) June 2014


Because surely $\Delta L = 0.24*1.5 = 0.36$ so therefore $\frac{\Delta L}{L} = \frac{0.36}{1.5} = 0.24$

What am I doing wrong?

The question is asking for stress not strain