Edexcel FP2 Official 2016 Exam Thread - 8th June 2016

Just watched the Hitler video, lol.

64/65 for an A or A*?

Question didn't ask you to show it.

arsey make a mark scheme!!

But it said 'Using De Moivre's Theorem'. Technically, z^n -z^-n = 2i sin theta is not De Moivre's Theorem, it's an application of it.

I showed it just in case, cause doing the question without it would not have used de Moivre's

Just watched the Hitler video, lol.

Ok, would I have lost all the marks for not doing this?

Ok, would I have lost all the marks for not doing this?

IIRC it was 5 marks, wasn't it? I'd say 2-3 marks tops.

Also, for the polar area question, I did C1-C2 instead of C1+C2, giving me an answer of 15ish instead of the 32.5 that most people seem to have got. If all the following working was correct, How many marks might I lose (I think that part Q was 7 marks)

You would get marks for integrating correctly and substituting limits. So I would have thought that you would get 4/7

But it said 'Using De Moivre's Theorem'. Technically, z^n -z^-n = 2i sin theta is not De Moivre's Theorem, it's an application of it.

I showed it just in case, cause doing the question without it would not have used de Moivre's

Being pedantic: z^(n) - z^(-n) = 2i sin (n theta)

Any application of the theorem would be classed as 'using' the theorem. After all, the method only works if the theorem does too.



I also did that, they might not give credit for it but it's better to be safe than sorry

But it said 'Using De Moivre's Theorem'. Technically, z^n -z^-n = 2i sin theta is not De Moivre's Theorem, it's an application of it.