Linked pair pilot - Applications of Maths (Edexcel) 24/05/2016

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Reply 40

Lauren0812

Original post by BenTLad

it weren't b

The perimeter of PSRQ was half of ABCD?

Reply 41

BenTLad

Original post by Lauren0812

The perimeter of PSRQ was half of ABCD?

it was 3.25 cha unlucky, i made sure that i was right aswell, and also 4.66666666666 seems almost inevitably incorrect as edexcel barely ever use bizaare numbers for an x value unless the total value is an integer or an number under 3 significant figures

Reply 42

Lauren0812

Original post by BenTLad

Lol cheers. Just realised that I didn't read the question correctly and thought that the sides were x+10 and 2x+ 3, not X+ 10 and X+ 3. Should only lose 1 method mark, maybe 2 so it's all good :smile:

Reply 43

Lauren0812

Yeah that's right I read the question wrong lmao

Reply 44

username2574405

Original post by BenTLad

is that you just remembering the question or is their a way to access the test we did today?

Unfortunately I just remembered it, I haven't seen the paper since the exam

Reply 45

Tojsagay

Original post by BenTLad

is that you just remembering the question or is their a way to access the test we did today?

Remembered it.

Reply 46

username2574405

Original post by 11staylor

The t question and the rectangle in the shape is the same question! :smile:

Don't worry too much about it...some of the questions were pretty difficult :s-smilie:

Theres always Applications 2 as well, I'm sure you will do fine :p:

Ah yes they were. Hopefully! I only got a C last year so I'm praying for a B, maths is not my forte :crossedf:

(edited 7 years ago)

Reply 47

BenTLad

Original post by Lauren0812

as long as you have applied the correct working out to your wrong answer u will only lose a mark.

Reply 48

Lauren0812

Original post by BenTLad

as long as you have applied the correct working out to your wrong answer u will only lose a mark.

Really annoyed because I wanted to beat my mark from last years exam for methods. Although I know I've lost at least 4 marks from this question and the angle in the kite just because I don't RTFQ :frown:

so annoyed tbh, at least I've learnt something though ahaha!

Reply 49

miniboy

Unofficial mark scheme (some of it):

75 Euros for the first question,
31 degrees for the kite,
87.5% for the last one,
13 for stratified sample,
the supermarket was the better choice,
linear programming - shade the bottom part and the point (44,44) to find the profit (which is £19000 and something),
4x for the rectangle in the rhombus question,
3.25 for the rectangle and the big rectangle (perimeter)
the flowchart - the £0.25 is replaced by £0.30 ....

so far, gonna make the rest in a bit.

Tell me if anything needs changing ../

(edited 7 years ago)

Reply 50

kusher321

Does anyone know the grade boundaries?

Also, I'm a new member.

Reply 51

kusher321

Original post by miniboy

unofficial mark scheme (some of it):

75 euros for the first question,
31 degrees for the kite,
87.5% for the last one,
13 for stratified sample,
the supermarket was the better choice,
linear programming - shade the bottom part and the point (44,44) to find the profit (which is £19000 and something),
4x for the rectangle in the rhombus question,
3.25 for the rectangle and the big rectangle (perimeter) ....

So far, gonna make the rest in a bit.

Tell me if anything needs changing ../

we need the rest of the unofficial mark scheme!!! bump

Reply 52

jayg123

Original post by Lemuelc14

Did you get 4x for the t expression in that question about the shaded rhombus and the rectangle

16 x

Reply 53

Tojsagay

Original post by kusher321

Does anyone know the grade boundaries?

Also, I'm a new member.

I'm expecting the boundaries to be no lower than 84 for an A* and no higher than 88 for an A*. Tell me if you want the other ones.

Reply 54

Uvesh123

Original post by miniboy

Is the linear programming one not (92,20) and that gets a profit of 19,120 because when it's (44,44) I only got a profit of around 17000 something

Reply 55

glassriver

I got t=4√10x for the rhombus question, seems like I should've learnt the formula for that (or actually read the question properly and realised that the area couldn't have been the width times the height).