Edexcel AS/A2 Mathematics M1 - 8th June 2016 - Official Thread

i suppose your right in the sens that you sould know T<25. However, in past mark schemes when there have been similar questions, the marks have been assigned for labelling the correct values and each line having the correct shape and values assigned to it. So as long as the overall shape is right and the right values are assigned to the correct point I would think you would still get full marks.

For question 2b, I am pretty sure it said the force exerted by the brick on the pan not the other way round, so wouldn't the answer be 1.5g (14.7N)

I did F=ma on the pan and got the same answer as those who did F=ma on the brick (15.5 N). It's the same answer both ways.

20.6-0.5g-R = 0.5x0.5 (ignoring the weight & mass off the brick as we aren't considering the whole system, just the forces on the pan)
15.7-R = 0.25
15.7-0.25 = R = 15.45 -> 15.5 N (3sf)

It's not 14.7 N because of the acceleration

Wait wait wait why is it not:

R - 0.5g = 0.5 x 0.5
R - 4.9 = 0.25
R = 5.15N

Using N3L, the force extered is 5.15N

???? Most of the people I took the exam with did this. If this is wrong, please explain ;-;

The mass of the brick is 1.5 and not 0.5

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guys for the vector question 7.. i did some triangle stuff and ended up using the cosine rule.. and i somehow got my answer as 2.5 but then for some reason square rooted it as my final answer (don't ask why) but do you think ill get many method marks for using the cosine rule? cause i did get 2.5 somehow

I did F=ma on the pan and got the same answer as those who did F=ma on the brick (15.5 N). It's the same answer both ways.

20.6-0.5g-R = 0.5x0.5 (ignoring the weight & mass off the brick as we aren't considering the whole system, just the forces on the pan)
15.7-R = 0.25
15.7-0.25 = R = 15.45 -> 15.5 N (3sf)

It's not 14.7 N because of the acceleration

Btw thanks for when you said v=v0 + ta
that came up in the exam

Bro did the same thing i got 2.46 aprox. 2.5 so i dont know.

question asked for magnitude so you would lose one mark for that question.

for part a you dont know if T is faster or slower than 25 seconds at that part so I don't think it matters, marks for graphs come from labelling the correct values and that the lines have the correct shape

Could someone explain to me why the force exerted by the brick is 15.45N and not just its weight, 14.7N. I understand it's accelerating upwards and so there must be a net upwards force greater than the weight. The difference between the force and the weight is the force required to make it accelerate at 0.5m/s^2, so net upwards =1.5g + 0.5x1.5=15.45. Surely though, this is the force that the pan exerts on the brick and not what the brick exerts on the pan? Or am I correct and have I just messed up when reading the question and it's actually asked me to find the force of the pan on the brick?

hopefully got 73/75 on this, just waiting to be shafted by C3 and C4

Sorry to burst your bubble on the first one.
The vector was 20i - 5j, if you draw it you'll see the bearing would be 90° + arctan(5/20) = 104°.

can someone explain question 2b ?