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UNOFFICIAL MARKSCHEME Edexcel Maths Calculator paper 09/06/2016

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Reply 1800
Avatar for ad4m
ad4m
8
There are two methods for trial and improvement. In this case, one method returned 3.7 and the other returned 3.8.
Original post by ...???
For stem and leaf do u have to put 9/20 as a decimal to get the full marks


absolutely not on mark schemes it might give it as a decimal but it will say 'oe' (or equivalent). This is because the actual maths is correct
Original post by gro
what was ur answer? I got the right answer but i wrote yes for some reason, lol, silly me. but if you made the same mistake its because 7500 and under would mean the car depreciated by 50% as it costed 15000. If it was over this price, it was not as low as half yet.


I'm doing this because my friend just sat the paper and was confused, im doing A2 further atm and i got that the final value of the car was 6150 meaning it has depreciated beyond its half point (7500)?
Do you think the grade boundaries will be 170? Or even higher?


Posted from TSR Mobile
Guys, do you reckon for the last question there will be a range of answers? For example, a lot of people got 80.4 degrees, I got 80.1 degrees with other people as well. Please quote me with an answer!
looks like ive failed maths then
Reply 1806
Avatar for Rxkaa
Rxkaa
1
Original post by Nightly
Guys, do you reckon for the last question there will be a range of answers? For example, a lot of people got 80.4 degrees, I got 80.1 degrees with other people as well. Please quote me with an answer!


People only got a range of answers cause they rounded their numbers instead of using the full digits, so the people who didnt do that will probably got full marks


Posted from TSR Mobile
What if I used 3.142 for pie?
Original post by ellamoon_22
No its like saying 6-2 is the same as 2-6. They are different so u dont cancdl out


You can cancel out 3-x and x-3 in this way. Change the first top one with minus in front of one bracket to get -(3-x). You didn't change anything as minus turns it into X-3 when you get rid of the bracket which is the original one. It's like multiplying it by -1 but we never write -1, only as minus (-) in front of the bracket. Think of the rule (-) x (-) is (+) or (-) x (+) is (-). Same with division. But be careful as cancelling both brackets with the same value will live that minus out of brackets. It will give you a negative answer -1 or better say just minus. So, your example 6-2/ 2-6 becomes - (- 6+2)/ (2-6) which is exactly as you can write as - (-4)/ -4 = 4/-4 = -1 as rules of division and multiplication of the same and different signs (minus and plus) are the same.

I don't know what was the original exam question, but many here posted the answer as 3-X / (x-3)(3x +4). If correct, You do this -(-3+x) /(X-3) (3x+4), which is nicely written as -(x-3) / (x-3) (3x+4). See, you have the same brackets with (x-3) but one is with minus. So it must be minus in your answer as minus divided by plus is minus (-).
So, cancelling out two brackets with -(x-3) by (x-3) you end up with -1 / 3x +4 because of that minus (-) in front of the top bracket. You can write that minus right in front the division line of the fraction.

I really hope you understand it. If not, I am willing to explain it further. Cheers!
(edited 7 years ago)
that was an A* last year i think, that will be a high A or low A* if grade bouandries are lower
Original post by TheNerdxP
Damn. You see I thought when it came to people you can't round another person as you don't have an extra 0.2 of a person, so I rounded it down :/


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I wrote 10 aswell as my reasoning was exactly the same as yours. I think both 10 and 11 are accepted as they have been in past years👏🏻
Reply 1811
Avatar for g3ob
g3ob
11
Original post by erodedsoul

Thank you :smile:
I got 80.4
Reply 1813
Avatar for GKT
GKT
8
Original post by anna-mackinlay
http://www.thestudentroom.co.uk/showthread.php?t=4153261&p=65600663#post65600663

This is someone elses answers so don't guarntee that they are all correct but its a rough overview. I'll keep looking out for another one


Thanks
Tbh I loved this paper. Just lost mark for stupid mistakes
Reply 1815
Avatar for aw30
aw30
1
Original post by Purpleunicorn197
Hi I'm going to start and unofficial markscheme so add your answers
Reps are not necessary but would be appreciated :smile:

Sorry for the hold up with the questions:colondollar:
1. Order numbers correctly and include a key (Stem and leaf) (3 marks)
b) 9/20=
0.45 (2 marks)
2a. 5a*2b*3c =
30abc (1 mark)
b. Factorise fully 3y +6 =
3(y+2) (1 mark)
c. Expand x(x-3)=
x^2-3x (1 mark)
3. Perimeter of a rectangle with side lengths x and x+4 is 45
x+x+x+4+x+4= 4x+8
4x+8=45
4x=37
x=9.25 (3 marks)
4. Smallest packet was best value for money because it was cheapest per bag of crisps (4 marks)
5. 4 times as many red than green: There were 0.4 blue and 0.15 yellow.
0.4+0.15+4x+x=1
0.55+5x=1
5x=0.45
x=0.09
4x=0.36
Green- 0.09 Red- 0.36 (3 marks)
6a. Body mass index= m/h^2
Mass= 50kg
Height= 1.57m
20.3 (2 marks)
b. What mass will result in a BMI of 21 with a height of 1.8m
68.04kg (2 marks)
c. Tom's skis can be a maximum of 145% of his height what is their max. tenght (Tom is 1.8m)
2.61m (3 marks)
7. Trial and error. x^3-5x=34 with a number between 3 and 4
3.8 (4 marks)
8a. Photographs with of width 720 pixels and a height of 540 pixels what is the ratio width:height in its simplest form?
4:3 (2 marks)
b. The person now wants the ratio to be 2:3, without changing the width of the picture, what is the new height?
480 pixels (2 marks)
9.x= 124 degrees (4 marks)
10. Mean of grouper freq. table 396(freq.*midpoint total)/50 (freq. total)
7.92 (4 marks)
11. Colin's drive to work
£42.29 (5 marks)
12. The middle angle of a pentagon
x=144 degrees (4 marks)
13.
-2 -1 0 1 2
-1 3 1 -1 3 (2 marks)
Draw curve (2 marks)
14. steel bar with length of 120cm and a cross sectional area of 72cm^2 and a density of 8g/cm^3. A trolley can carry 250kg so how many bars can it carry?
3 Bars (5 marks)
15. Pauls buys a car worth 15,000 pounds and the value depreciates by 23% in the first year and 18% after the first year. Has Paul's car lost half of its value in theree years?
No, because 7766.22 was greater than 7500 pounds (4 marks)
16. Median on cumulative freq. graph
128g (1 mark)
b. Use graph to find interquartile range
11g (2 marks)
17. Triangle with sides 15.6cm (opp), 18(hyp). Angle is split into 2, 30 degrees and x degrees. the whole angle is 60.1 so
x=30.1 (4 marks)
18. 10a^5b^4 (2 marks)
b. y= 5p^2-x (3 marks)
19. 51 out of the 234 were maths in yr 12 so 50 * 51/234
11 males (2 marks)
20. 3x^2 + 6x -2
x= 0.29 or x= -2.29 (3 marks)
21. v=14 to 2 s.f u= 8.7 to 2 s.f
What is the upper bound of I when I= 5(v-u)
29.25 (3 marks)
22. Histogram -F.d- 1.6, 3.2, 2.4, 1.8, 0.3 (3 marks)
23. Perimeter of the shaded part of the sector.
Measurements were 4+4+5/2pi+25/6pi
28.9 (3 marks)
24a. Simplify (3-x)/3x^2-5x-12
-1/3x+4 (2 marks)
b. Write are one fraction in its simplest for (x/x-1)- (x/x+1)
2x/(x+1)(x-1) (3 marks)
25. Triangle with side lengths 7 and 8 finding the top angle using 1/2absinC , sine rule and cosine rule
80.4 (6 marks)


looking through this mark scheme i think i would be able to get around 55 marks which 100% secured my B grade in Maths
Original post by aw30
looking through this mark scheme i think i would be able to get around 55 marks which 100% secured my B grade in Maths


Not bad. I got between 88 and 93 percent.
Original post by Rxkaa
Yes as 45%=0.45=9/20


Posted from TSR Mobile


chill ,cheers
the area of a triangle is 1/2 x a x b x sin(c). so you rearrange it to find sin(c) and then inverse sine it to find the angle on the left. then you i used the cosine rule to find out the length of the side opposite to the angle you just worked out (the right hand side length). then i used sine rule and got 80.4 degrees.
I had a bloody stomach ache in this exam. I couldn't think properly, it was so annoying. I managed to finish the paper which i am soooooo happy about but i swear im going to make my stomach regret what torture it put me through today :angry:

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