I just worked back from ur answer and that means ur original velocity was 32.2ms^-1 and I don't know how you got that. Since that means ur horizontal velocity was 31.58ms^-1.
I just worked back from ur answer and that means ur original velocity was 32.2ms^-1 and I don't know how you got that. Since that means ur horizontal velocity was 31.58ms^-1.
It said to show that the time was about 0.6s so I usd the more accurate time of 0.57s and I got my values.
It said to show that the time was about 0.6s so I usd the more accurate time of 0.57s and I got my values.
I got 0.64 by using v=u+at by I'm guessing you used S=ut+1/2at^2 which is rather interesting. The funny thing is both are correct but the reason they are different is probs because the value we got for the initial velocity was probably a rounded value.
I got 0.64 by using v=u+at by I'm guessing you used S=ut+1/2at^2 which is rather interesting. The funny thing is both are correct but the reason they are different is probs because the value we got for the initial velocity was probably a rounded value.
Will I be marked down for getting that answer do you think?
Will I be marked down for getting that answer do you think?
I don't think there is much reason to assume you're incorrect; although most people in know used the v=u+at because s=ut+1/2at^2 also gives you an answer of t=0.7 something.
I don't think there is much reason to assume you're incorrect; although most people in know used the v=u+at because s=ut+1/2at^2 also gives you an answer of t=0.7 something.
Yeah that's true. God dammit I have mad a few errors now, I hope that I don't get below an A, will be really pissed off if I do get below an A.
I think the only thing that OCR messed up with this paper was that they had a lot of questions where it was a show that and then lead onto another question; so it was hard to know which value to know to use. :c