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Edexcel AS/A2 Mathematics M2 - 17th June 2016 - Official Thread

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Reply 40
Avatar for maddywald
maddywald
OP
3
Original post by jamestg
I don't like being a groan and/or being salty, but you could've credited me for the OP format :colonhash:


didnt know that was a thing m80 soz have edited it
Joined


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Hey, in the question attached, how do you get the 3cos30 value for the centre of mass of that particular rod? Thanks.

EDIT: Nevermind, got it now.
(edited 7 years ago)
tsr.png93.0KB
This looks like a really easy moments question but for some reason I am unable to follow the markscheme for the first part.
I can understand the moments for the weight but then it comes for resolving to try and get the T perpendicular to the distance to A I can't seem to draw the angles right :s-smilie:
Untitled.png56.8KB
Original post by Windowswind123
This looks like a really easy moments question but for some reason I am unable to follow the markscheme for the first part.
I can understand the moments for the weight but then it comes for resolving to try and get the T perpendicular to the distance to A I can't seem to draw the angles right :s-smilie:


Have you noticed that triangle ACD is isosceles? AC = AD = 2.5a

Are you using T x perpendicular distance from A to the strut? It is easier in this case than splitting the T up I think.
(edited 7 years ago)
I'm getting mid70s to low 80s at the moment, do you think I can get an A on Friday?

:frown: nervous


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Original post by tiny hobbit
Have you noticed that triangle ACD is isosceles? AC = AD = 2.5a
.

Ah yeah so angle ADC = 30
Thanks
Does the constant of integration remain the same for acceleration->velocity->displacement ?


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Can anyone help out with part ii? Not sure where the mark scheme is getting these numbers from (especially root(1300)) m2 capture 3.JPGm2 capture 4.JPG
m2 capture 4.JPG14.0KB
Reply 49
Avatar for Brailey
Brailey
2
Original post by Don Joiner
Does the constant of integration remain the same for acceleration->velocity->displacement ?


Posted from TSR Mobile


No -

For Displacement it is zero if it starts at the origin so make your check it says in the question, if not then there will be a constant.

For Velocity I have not done a question where it is zero, I'm assuming you can work out the constant but if you don't I can explain!

For Acceleration you wont get a constant as you will not be asked to integrate a function that goes to acceleration. For example the derivative of displacement is velocity and the derivative of velocity is acceleration and thus there is no derivative of acceleration.

Hope this helps! :smile:
Can someone help me out with this question

http://postimg.org/image/pb2x5eu6p
Original post by fpmaniac
Can someone help me out with this question

http://postimg.org/image/pb2x5eu6p


Assuming you know how to find the centre of mass of the triangle, you know that the centre of mass of the is directly below the poiny from which it hangs, s you can use that to find the angle

Posted from TSR Mobile
Im dont know how to work these out so would appreciate help:
http://postimg.org/image/j4rqcqfkh

http://postimg.org/image/dd092ibyv
12 b on there
Reply 53
Avatar for jtt1998
jtt1998
Does anyone have the June 2015 question paper?
How on Earth did they get that answer? Surely it is e<5/3 ?
tsr.png8.9KB
Reply 55
Avatar for kennz
kennz
8
Can someone help me with this question please

http://www.thestudentroom.co.uk/showthread.php?t=3892047
Original post by fpmaniac
Can someone help me out with this question

http://postimg.org/image/pb2x5eu6p


Find centre of mass of the triangle, then that will be directly below O.

Original post by paradoxequation
How on Earth did they get that answer? Surely it is e<5/3 ?


You're right, looks like it should be e<5/3, typo maybe?
Original post by fpmaniac
Im dont know how to work these out so would appreciate help:
http://postimg.org/image/j4rqcqfkh

http://postimg.org/image/dd092ibyv
12 b on there


I'm struggling with the first one, I'm going to look at it again.
I've got an answer for 12b though, how far have you got? Have you tried resolving the situation horizontally and vertically to get equations for the horizontal and vertical components of the force at the hinge?

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Original post by pineneedles
I'm struggling with the first one, I'm going to look at it again.
I've got an answer for 12b though, how far have you got? Have you tried resolving the situation horizontally and vertically to get equations for the horizontal and vertical components of the force at the hinge?

Posted from TSR Mobile


I dont know how to draw the force exerted on B by the wall so i havent gotten very far.
Original post by fpmaniac
Im dont know how to work these out so would appreciate help:
http://postimg.org/image/j4rqcqfkh

http://postimg.org/image/dd092ibyv
12 b on there


Original post by pineneedles
I'm struggling with the first one, I'm going to look at it again.I've got an answer for 12b though, how far have you got? Have you tried resolving the situation horizontally and vertically to get equations for the horizontal and vertical components of the force at the hinge?Posted from TSR Mobile




Here's my solution to 11

ImageUploadedByStudent Room1465833636.242747.jpg
ImageUploadedByStudent Room1465833692.288994.jpg


Posted from TSR Mobile
(edited 7 years ago)

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