A trimer is a polymer with only 3 monomers in it, the answer to this question is basically the product formed in step 3 but with an extra monomer of ethanal added. so it should look like this i think:
Please could you explain why there is another -OH group in the trimer? As far as I see it the molecule X is an aldehyde with a hydroxyl group and ethanal is being added to it so there should be only one OH?
How did you get ch2 as the ef i dont get it - i did the pp last nyt i got c3h6 as the usuall molcular formula is c6h12
The empirical formula is the simplest whole number ratio in whichthe atoms of each element in a compound are found.
The formula of cyclohexane is C6H12. Dividing each number of atoms by the smallest number (6) gives us CH2 as the empirical formula. CH2 cannot be further simplified to a whole number ratio and so is the simplest whole number ratio.
The empirical formula is the simplest whole number ratio in whichthe atoms of each element in a compound are found.
The formula of cyclohexane is C6H12. Dividing each number of atoms by the smallest number (6) gives us CH2 as the empirical formula. CH2 cannot be further simplified to a whole number ratio and so is the simplest whole number ratio.
I usually / by 2 to get the simplest ratio until you cant half anymore to get a simple number - just curios why it didnt work here
the mark scheme called the ester (1)-methylethyl ethanoate, however i didn't put the(1) as i didn't think it was needed as the methyl group couldn't come off anywhere else, would i get the mark?
the mark scheme called the ester (1)-methylethyl ethanoate, however i didn't put the(1) as i didn't think it was needed as the methyl group couldn't come off anywhere else, would i get the mark?
If the one was in brackets then I think you can still get the mark
Please could you explain why there is another -OH group in the trimer? As far as I see it the molecule X is an aldehyde with a hydroxyl group and ethanal is being added to it so there should be only one OH?
here you go: You basically have to repeat the steps to add another monomer. I forgot to put a OH- which is formed as well on the last step