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Edexcel S1 - 15th June, 2016 [Exam Discussion]

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Original post by Willandy123
Yo guys, do we have to learn all the proofing for all the equations in S1, if so, anyones got all the proofs?

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You dont need to learn the proofs for any of the formulas.
image.jpg
For the June 15 paper on question 3 where it asks to determine whether its statically independent I did what Alwaus gets me the marks in past papers but for this one they wanted something different and I don't get it.
My failed solution ^
Original post by Kadak
When they say give an interpretation of b ,what is usually meant ?


b is the gradient, so for every one unit increase in x, the y increases (if b is positive) or decreases (in b is negative) by the value of b
Reply 403
HEY AGAIN can someone pls help me with june 2013(R) question 5 d) and e).. I really don't understand the theory behind it - Here's the paper's link: http://qualifications.pearson.com/co...e_20130517.pdf
Original post by Siddhart1998
image.jpg
For the June 15 paper on question 3 where it asks to determine whether its statically independent I did what Alwaus gets me the marks in past papers but for this one they wanted something different and I don't get it.
My failed solution ^


I always do:
If they are independent then P(B|C) = P(B)
P(B) = 20/80 = 0.25
P(B|C) = (4+3)/28 = 0.25
Since P(B) = P(B|C) the events are independent
(edited 7 years ago)
Reply 406
Original post by wenogk
HEY AGAIN can someone pls help me with june 2013(R) question 5 d) and e).. I really don't understand the theory behind it - Here's the paper's link: http://qualifications.pearson.com/co...e_20130517.pdf


5d) The value is unchanged
Reason is Sxx = Sum(xbar - x)^2
so x = 6
xbar is sum of x divided by number of items
sum of x was 60 (divided by 10 gives xbar of 6)
Add 6 (turner has 6 characters) and we have 66/11 (one new item)
so x bar is STILL 6.
Since x is also 6 there is nothing to add to Sxx, so it still equals 28


They did use 0.75.

P(X<Q3) = 0.75. Then look at the table to see what value of Z gives 0.75 - you'll find that it's 0.67.

So, 0.67 = q3-mean/s.d and then solve for q3.
Hi,
If the probability is for example P([CUB]), what do the square brackets mean?
Do you guys think we will get an easy or hard paper tomorrow ?
Original post by rose1234
Hi,
If the probability is for example P([CUB]), what do the square brackets mean?


Probability of C or B occurring so you add P(B) +P(C).
U=OR(add the probabilities).
U upside down means =ADD(multiply the probabilities).
I think the square brackets represent the order in which you prioritise the brackets e.g.do the ones in the square before you do the normal one.
(edited 7 years ago)
Does anyone else find June 2015 IAl impossible of just me?
Reply 412
Original post by Siddhart1998
image.jpg
For the June 15 paper on question 3 where it asks to determine whether its statically independent I did what Alwaus gets me the marks in past papers but for this one they wanted something different and I don't get it.
My failed solution ^


the method you used is right. 0.0875=7/80
however how did you get 0.25 for P(b/\c) (maybe venn diagram was wrong). P(b/\c) is also 7/80 (4+3/80) so as they're equal, they're statistically independant
Reply 413
Original post by Kadak
Do you guys think we will get an easy or hard paper tomorrow ?


I bricking it for tmo, as im assuming it's gonna be harder. I've done every PP over the last week chronologically (2005-2015) and my overall mark has slightly decreased as I came to the more recent ones. They're getting wordier and expecting to APPLY our knowledge of current topics more frequently, on styles of questions we've just never seen before.

C1 & C2 (2016) provided as evidence for this, as I'm sure many found these papers slightly harder than previous PPs, and i think S1 will generally follow this trend. Hopefully it won't be harder but all we can do now is pray for the best! :redface:
guys any important points and tips to write in questions where dey ask us to compare to events specially in the case of 2 box plots
Reply 415
In question 2f of the 2016 IAL paper, why is the probability passing 1/2 instead of 75%? Is it just common sense that chance of passing is 1/2?
Attachment not found
Could someone possibly explain to me how to get this answer I'm lost..s1-1.JPG
best way to revise probability and normal distribution?
Reply 419
Original post by arrow_h
Attachment not found
Could someone possibly explain to me how to get this answer I'm lost..s1-1.JPG



Prob a- wakes before 6:30
Prob b- goes for a run

draw a VENN DIAGRAM:
from reading the question we can see-
P(A)= 0.7
P(B) 0.35
P(A'/\B')= 0.22 (outside of two circles)

remember: P(AuB)= overall probability within two circles
so P(AuB)= 1 (total proability)- 0.22 (probability lying OUTSIDE of circles)
=0.78

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