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Aqa chem 4/ chem 5 june 2016 thread

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What was the eqn to the first question where propanoic acid acts as a base and reacts with nitric acid????
Original post by Suits101
I've just checked markschemes:

Why is chloroethanoic acid a stronger acid than ethanoic acid? (1)

1 mark for:

Cl is (more electronegative so) withdraws electrons
OR negative inductive effect of Cl

Second mark for:

Weakens O-H bond
OR reduced negative charge on COO-
OR stabilises COO- (more)


For distinguishing between P and Q:

Reagent: AgNO3 OR Na2CO3/NaHCO3 OR water OR named indicator
P: no visible change/no reaction
Q: (white) ppt OR effervescence/CO2/fumes/exothermic OR fumes/smell OR acid colour

Words in brackets aren't needed

Are u sure about the p and q one????? Cus I put Agno3
If I spelt Nucleophilic as 'Nucleophillic' , will I get penalised?

Somebody please come up with a mark scheme
Original post by Nancyeponine
There's no point the stitches one is a suggest so it's meant to be hard and it was on the syllabus anyway because the answer was it hydrolyses and so can he removed post surgery


no it was an easy question, the answer was it contained polar bonds so would (biodegrade) by themselves
Reply 1164
Original post by PaddysChemistry
Anyone get OH-CH2-CH2-C(CH3)2-O-CH3 for 9?


ImageUploadedByStudent Room1465921486.693938.jpg
I thought there had to be a group like this?


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Original post by Cadherin
Was P the RCH2Cl and Q the acyl chloride?


I'm going to be honest I'm unsure.

I believe that was right.
Original post by Ginpls
What was the eqn to the first question where propanoic acid acts as a base and reacts with nitric acid????


The propanoic acid accepts a H+ and the nitric acid becomes NO3-


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Original post by Mammothman
Yes I got exactly that, and using the hnmr data deduced that it could only be that...then spent all my spare time trying to figure out alternate structures that didn't involve a tertiary alcohol...of which there were none.


there is. i think i got the right answer
for last question i got


CH3-CH2-CCH3(OH)-CH2-CH2OH-CH3

think it's definitely wrong, but hey ho
Original post by minjinoor
it was definitely 8 peaks...

what a SNEAKY, PIECE OF CRAP paper - AQA have it in for us this year! it was manageable (except for q9) but it may as well have been called 'Acyl Chlorides 101'.
Also wtf was Chem 1 doing in there - hydrogen bonds, percentage mass, molecular formula ?!?!
psshht A in chem gone


I can assure you it was 9 peaks.
is the unofficial mark scheme up yet
Original post by medscoolhopeful
Yep! Just trying to forget about today and move on :frown:


Same but it's not working :'((((

Original post by Capsicle102
Is that OCR? If so, yes :smile:


Another paper from AQA :tongue:

Spoiler

Good luck though! :biggrin:

Original post by HannahC-H
Yah :-(((((((((



Awww we'll get through this.... (Maybe)
I said it was more soluble and so is more soluble in bodily fluids- blood, water
Guys please, does anyone know what happens when you forget to write the date down on extra paper that you use?? I remembered to write everything else, just completely forgot about the date!! I'm having a huge panic, almost half my answers were on that :frown:
Original post by Kaya22
there is. i think i got the right answer


Can't be a tertiary alcohol it clearly stated that when K2Cr2o7 was added it went from orange to green


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Reply 1175
Hitler reacts is on YouTube now, laughing away the tears
Original post by FireBLue97
Why initial rates were used question
The temperature would change would affect the rate so the rate will change so initials are used
Then for the graph initial question draw a tangent to line or curve with passing through point at 0 seconds and calcuate gradient
2 or 3 marks for this 2 questions


I put exactly the same for second question.

It was 2 marks.
Original post by Mammothman
Yes I got exactly that, and using the hnmr data deduced that it could only be that...then spent all my spare time trying to figure out alternate structures that didn't involve a tertiary alcohol...of which there were none.


Omg I literally spent half an hour on that question- the whole paper was an utter joke and embarrassment.

But yeah either wayif it's wrong we will prob get a mark for identifying the -o- and the -oh ?
I got (CH3)2CH-CH2-O-CH(CH3)-CHOH for the last structure. The middle may be the wrong way around, as I can't remember, but I put the primary alcohol on the end and a di-methyl group on the other. Did anyone get the same?
Original post by minjinoor
for last question i got


CH3-CH2-CCH3(OH)-CH2-CH2OH-CH3

think it's definitely wrong, but hey ho


It was a hydroxy ether I'm afraid.

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