S1 Help Please.
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Original post by Glavien
Ohhh, that took me a while too understand. Thanks for that.
No problem.
Original post by Glavien
Ohhh, sorry about that, I was doing P(1 and 1) P(3 and 3) P(5 and 5) twice by mistake. Thank you!! 
May I just add in (it's two weeks old but..) you could just find the probability that it is odd (so add P(x=1) + p(x=3) + p(x=5)) and then square it and get the same result. So you get (0.62)^2 = 0.3844. It's a bit quicker than finding all the potential ones!
Original post by iMacJack
May I just add in (it's two weeks old but..) you could just find the probability that it is odd (so add P(x=1) + p(x=3) + p(x=5)) and then square it and get the same result. So you get (0.62)^2 = 0.3844. It's a bit quicker than finding all the potential ones!
Yes, he's aware of that.
Original post by Zacken
Yes, he's aware of that.
Ahhh my bad! Didn't fully read everything!
Original post by iMacJack
Ahhh my bad! Didn't fully read everything!
No problem, he also just asked the same question that you asked about Jan 2016 Q2(f).
Original post by Zacken
No problem, he also just asked the same question that you asked about Jan 2016 Q2(f).
Yep I just saw! I still don't fully get it though, hence another response on the other thread
Original post by iMacJack
Yep I just saw! I still don't fully get it though, hence another response on the other thread
Ah, alright.
Original post by THESTRESS
Hi, do we include the outlier in calculations?
No? Your post has no context and thus doesn't have a reasonable reply. Plus, you'd be better off posting this in another thread.
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