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FP1 AQA 15th June 2016 UNOFFICIAL MARK SCHEME (what you have been looking for)

My answers for this morning's exam, please let me know if you agree/disagree on answers!

Q1 Roots of Polynomials

(a) alpha+beta=6 [2marks]
alpha*beta=14

(b) 7X^2-4X+7=0 [5 marks]

Q2 Gradients using h

(a) -h-3 [3 marks]

(b) as h-->0 gradient-->-3 [2 marks]
when h=0 gradient= -3

Q3 Log graph
(a) show linear relationship log(Y)= Xlog(B) + Log(A) [2 marks]

(b)gradient was -0.4 [1marks]

(c) a= 316 [4 marks]
b=0.398

Q4 General Solutions

(a) k=6 [1 marks]

(b) x= πn+ π/2 [4marks]
x= πn+ π/3

(c) root 3 [2 marks]

Q5 summations

(a) show it equal to 3n(4n^2-1) [5 marks]

(b) n(2n+1)(2n-3)(n-1) [4marks]

Q6 parobola

(a) show a=2 [3 marks]

(b) k= 1/2 [6 marks]
k= -2
k=0

Q7 Complex Numbers

(a) -2+4i [3 marks]
-2-4i

(bi) i+qi=0 therefore q must beequal to -1 [2 marks]

(bii) p=4 q= -12-i [5marks]
p=-4 q= 4-i

Q8 Matrices

(a) matrix 4 0 [1 marks]
0 1
(b) stretch in x-direction SF4 [1 marks]

(c)matrix 0.5 -root3/2 [2marks]
-root3/2 -0.5

(d) matrix p= -2root3 [6marks]
-2

Q9 graph

(a) Asymptotes: x=0.5 x=2 y=0 [2 marks]

(b) Intersections: x=5/2 x=1 x=0 [3 marks]

(c) a sketch [3 marks]

(d) x<equal to 0 [3marks]
0.5< to x<equal to1
2<x<equal to 2.5
(edited 7 years ago)

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Reply 1
4a 5b 6b all wrong. k=1/6 5b u whrre ment to get 3 linear factor and 6b an euality with greater and less than sign
Reply 2
do u remember marks for each question
Reply 3
Original post by jojoj
4a 5b 6b all wrong. k=1/6 5b u whrre ment to get 3 linear factor and 6b an euality with greater and less than sign


Nope. It was pi/k so k=6
Reply 4
Original post by jojoj
4a 5b 6b all wrong. k=1/6 5b u whrre ment to get 3 linear factor and 6b an euality with greater and less than sign


Yeah you are right about about 5 (b) i just couldnt remember the factors but I'll work it out now :smile:

Thanks man!
Reply 5
Original post by henryhong
Yeah you are right about about 5 (b) i just couldnt remember the factors but I'll work it out now :smile:

Thanks man!


yeah ur answer about k is right forgot it was pi/k thought it said pik
Reply 6
Original post by -jordan-
Nope. It was pi/k so k=6


Yep thats right! :colondollar:
Reply 7
Original post by jojoj
do u remember marks for each question


No but if you want I can find out for you?
Reply 8
Original post by henryhong
No but if you want I can find out for you?


yesss pleasee do that
Reply 9
Original post by jojoj
yesss pleasee do that


Okay Ill notify you once ive updated my answers
Reply 10
Original post by henryhong
Okay Ill notify you once ive updated my answers


I mean once ive updated the first post
Reply 11
Original post by jojoj
4a 5b 6b all wrong. k=1/6 5b u whrre ment to get 3 linear factor and 6b an euality with greater and less than sign


I knew something wasn't right about 5(b) what were your inquality signs?
and are the critical values atleast correct?
Reply 12
Original post by henryhong
I knew something wasn't right about 5(b) what were your inquality signs?
and are the critical values atleast correct?


5b should be n(2n+1)(2n-3)(n-1)? But definitely 4 linear factors, not 3.
Reply 13
Original post by aoxa
5b should be n(2n+1)(2n-3)(n-1)? But definitely 4 linear factors, not 3.


sorry I mean 6(b)
Reply 14
Original post by henryhong
I knew something wasn't right about 5(b) what were your inquality signs?
and are the critical values atleast correct?


sorry I mean 6(b)
Reply 15
Original post by henryhong
I mean once ive updated the first post


Its done :smile:
Original post by henryhong
My answers for this morning's exam, please let me know if you agree/disagree on answers!

Q1 Roots of Polynomials

(a) alpha+beta=6 [2marks]
alpha*beta=14

(b) 7X^2-4X+7 [5 marks]

Q2 Gradients using h

(a) -h-3 [3 marks]

(b) as h-->0 gradient-->-3 [2 marks]
when h=0 gradient= -3

Q3 Log graph
(a) show linear relationship log(Y)= Xlog(B) + Log(A) [2 marks]

(b)gradient was -0.4 [1marks]

(c) a= 316 [4 marks]
b=0.398

Q4 General Solutions

(a) k=6 [1 marks]

(b) x= πn+ π/2 [4marks]
x= πn+ π/3

(c) root 3 [2 marks]

Q5 summations

(a) show it equal to 3n(4n^2-1) [5 marks]

(b) n(2n+1)(n-1)(4n+3) [4marks]

Q6 parobola

(a) show a=2 [3 marks]

(b) k= 1/2 [6 marks]
k= -2
k=0

Q7 imaginary

(a) -2+4i [3 marks]
-2-4i

(bi) i+qi=0 therefore q must beequal to -1 [2 marks]

(bii) p=4 q= -12-i [5marks]
p=-4 q= 4-i

Q8 matrix

(a) matrix 4 0 [1 marks]
0 1
(b) stretch in x-directionSF4 [1 marks]

(c)matrix 0.5 -root3/2 [2marks]
-root3/2 -0.5

(d) matrix p= -2root3 [6marks]
-2

Q9 graph

(a) Asymptotes: x=0.5 x=2 y=0 [2 marks]

(b) Intersections: x=5/2 x=1 x=0 [3 marks]

(c) a sketch [3 marks]

(d) x<equal to 0 [3marks]
0.5< to x<equal to1
2<x<equal to 2.5



Thank you so much for this!!
From what I remember I had similar answers (:
Reply 17
Are you sure about the minus signs on 8d? And 7bii) I think you have your imaginary and real components mixed up
(edited 7 years ago)
[QUOTE=henryhong;65806509]My answers for this morning's exam, please let me know if you agree/disagree on answers!

Q1 Roots of Polynomials

(a) alpha+beta=6 [2marks]
alpha*beta=14

(b) 7X^2-4X+7 [5 marks]

Q2 Gradients using h

(a) -h-3 [3 marks]

(b) as h-->0 gradient-->-3 [2 marks]
when h=0 gradient= -3

Q3 Log graph
(a) show linear relationship log(Y)= Xlog(B) + Log(A) [2 marks]

(b)gradient was -0.4 [1marks]

(c) a= 316 [4 marks]
b=0.398

Q4 General Solutions

(a) k=6 [1 marks]

(b) x= πn+ π/2 [4marks]
x= πn+ π/3

(c) root 3 [2 marks]

Q5 summations

(a) show it equal to 3n(4n^2-1) [5 marks]

(b) n(2n+1)(n-1)(4n+3) [4marks]

Q6 parobola

(a) show a=2 [3 marks]

(b) k= 1/2 [6 marks]
k= -2
k=0

Q7 imaginary

(a) -2+4i [3 marks]
-2-4i

(bi) i+qi=0 therefore q must beequal to -1 [2 marks]

(bii) p=4 q= -12-i [5marks]
p=-4 q= 4-i

Q8 matrix

(a) matrix 4 0 [1 marks]
0 1
(b) stretch in x-directionSF4 [1 marks]

(c)matrix 0.5 -root3/2 [2marks]
-root3/2 -0.5

(d) matrix p= -2root3 [6marks]
-2

Q9 graph

(a) Asymptotes: x=0.5 x=2 y=0 [2 marks]

(b) Intersections: x=5/2 x=1 x=0 [3 marks]

(c) a sketch [3 marks]

(d) x<equal to 0 [3marks]
0.5< to x<equal to1
2<x<equal to 2.5

5b is n(2n+1)(2n-3)(n-1)
Question 8d is wrong, it's meant to be 2root3 2

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