One spin determines both of their scores. So basically, you have to work out the probability that 1/X > X and 1/X < X to work out who would win. There were five possible values for X; in two of them (3/2 and 2), Sarah won and in another two (-2 and 1/2), Rebecca won (the fifth option of -1 would have been a draw); sum the probabilities associated with those outcomes together (sorry but I can't remember the probability distribution) to get the answers of 0.475 and 0.375, respectively.
One spin determines both of their scores. So basically, you have to work out the probability that 1/X > X and 1/X < X to work out who would win. There were five possible values for X; in two of them (3/2 and 2), Sarah won and in another two (-2 and 1/2), Rebecca won (the fifth option of -1 would have been a draw); sum the probabilities associated with those outcomes together (sorry but I can't remember the probability distribution) to get the answers of 0.475 and 0.375, respectively.
I'm afraid I got 0.45 and 0.405, and I'm pretty sure both were correct.
I thought tet test was alright - a lot easier than C1 and C2. I dropped marks in the the venn diagram section because I only understood what to do in the question about B and D being independent in like the last 5 minutes
It says that 40 customers have rented a room and eaten breakfast It also says that 37 have rented a room and not had breakfast
Well, we worked out the chance of them having dinner given those conditions in the two previous parts, so all we needed to do was 40*0.45 + 37 * 15/37 to come to our answer of 18+15 = 33 customers.
For C1 I got 47/75 C2 I got 62/75 and for S1 I got 68/75. What overall grade would this be? I was thinking a high B maybe... If I resat C1 would I have a chance of raising my grade to an A?
One spin determines both of their scores. So basically, you have to work out the probability that 1/X > X and 1/X < X to work out who would win. There were five possible values for X; in two of them (3/2 and 2), Sarah won and in another two (-2 and 1/2), Rebecca won (the fifth option of -1 would have been a draw); sum the probabilities associated with those outcomes together (sorry but I can't remember the probability distribution) to get the answers of 0.475 and 0.375, respectively.
I'm afraid I got 0.45 and 0.405, and I'm pretty sure both were correct.