Maths year 11

Original post by z_o_e

Thank you so so so so much! ♥♥♥

Posted from TSR Mobile

No problem!

Reply 121

OP

Original post by 34908seikj

No problem!

Heyaaa I think you got this bit wrong.

You know for this we didn't work out 360-130

However for question 6 we did this

Question is the same the bearing of B FROM A
Posted from TSR Mobile

1466255182552.jpg32.9KB

1466255206277.jpg37.5KB

Reply 122

OP

Did these

Posted from TSR Mobile

(edited 7 years ago)

1466256621114.jpg30.5KB

1466256644205.jpg35.8KB

Reply 123

OP

Original post by 34908seikj

No problem!

You know hegarty maths did it a different way. Look...

He got 070 for the first one and it it wondered just like mine "of B from A".

And don't you think this answer will be 072?
Then

Posted from TSR Mobile

1466260132075.jpg31.3KB

1466260201287.jpg32.9KB

Reply 124

Original post by z_o_e

You know hegarty maths did it a different way. Look...

He got 070 for the first one and it it wondered just like mine "of B from A".

And don't you think this answer will be 072?
Then

Posted from TSR Mobile

Reply 125

Original post by z_o_e

You know hegarty maths did it a different way. Look...

He got 070 for the first one and it it wondered just like mine "of B from A".

And don't you think this answer will be 072?
Then

Posted from TSR Mobile

Will look at the other when I get home

Reply 126

OP

Original post by 34908seikj

Will look at the other when I get home

Tyyyx

Posted from TSR Mobile

Reply 127

OP

Original post by 34908seikj

Will look at the other when I get home

Can you explain these please

Posted from TSR Mobile

1466278033780.jpg33.6KB

Reply 128

Original post by z_o_e

Can you explain these please

Posted from TSR Mobile

Fixed my answers.

Put the x values into the given equation. Then just plot the points on the graph. It should be a straight line.

(edited 7 years ago)

Reply 129

OP

Original post by 34908seikj

Fixed my answers.

Put the x values into the given equation. Then just plot the points on the graph. It should be a straight line.

Oh yep yep I remember doing this. Btw is it possible if you can check my bearing answers I uploaded earlier. I'll upload them again from question 6 .

Posted from TSR Mobile

1466280072967.jpg33.8KB

1466280107438.jpg47.6KB

1466280121018.jpg43.6KB

Reply 130

Original post by z_o_e

Oh yep yep I remember doing this. Btw is it possible if you can check my bearing answers I uploaded earlier. I'll upload them again from question 6 .

Posted from TSR Mobile

Okay, gimme a couple of mins

Reply 131

Original post by z_o_e

Oh yep yep I remember doing this. Btw is it possible if you can check my bearing answers I uploaded earlier. I'll upload them again from question 6 .

Posted from TSR Mobile

For the first image is it B to A or A to B?

Reply 132

Original post by z_o_e

Oh yep yep I remember doing this. Btw is it possible if you can check my bearing answers I uploaded earlier. I'll upload them again from question 6 .

Posted from TSR Mobile

Here are my answers.

I did both because I didn't know which way around the question asked for, though I presume it was B to A.

(edited 7 years ago)

Reply 133

OP

Original post by 34908seikj

Here are my answers.

I did both because I didn't know which way around the question asked for, though I presume it was B to A.

YASSS I GOT MOST OF THEM CORRECT!!!

I did the graph and how do I solve these using the graph?
I just need an explanation for this not the answers thank you xxx

Posted from TSR Mobile

1466283137481.jpg29.9KB

1466283159333.jpg61.2KB

Reply 134

Original post by z_o_e

YASSS I GOT MOST OF THEM CORRECT!!!

I did the graph and how do I solve these using the graph?
I just need an explanation for this not the answers thank you xxx

Posted from TSR Mobile

Once you've plotted both the equations on the graph, you can find the values for X and Y (Hint: it's where both lines intersect)

Reply 135

OP

Original post by 34908seikj

Once you've plotted both the equations on the graph, you can find the values for X and Y (Hint: it's where both lines intersect)

the solution??
But what if in the exam is asks me this how do I figure it out on the graph? And it's not asking for the solution it's asking me for those points.

Posted from TSR Mobile

(edited 7 years ago)

Reply 136

Original post by z_o_e

the solution??

Posted from TSR Mobile

"I just need an explanation for this not the answers thank you xxx "

Lol X =1.5 Y = 2

Reply 137

OP

Original post by 34908seikj

"I just need an explanation for this not the answers thank you xxx "

Lol X =1.5 Y = 2

Yep I got this :smile:

Posted from TSR Mobile

Reply 138

yepthatsme

3

Go through every past paper.

So do the paper. Then, mark it and see where you lost all your marks or got questions wrong. Cover that WRONG working you did last time and re-attempt the question seeing if you got it right now...

Reply 139

OP