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Could someone explain how to solve part d please?

the answer to part c is x=6-3y^2

thanks:smile:
Original post by Katiee224
Could someone explain how to solve part d please?

the answer to part c is x=6-3y^2

thanks:smile:


I think it is k=2, if you substitute the range of t into y, the Max you can get is 2 and min is -2
Reply 2
Original post by JasPuddy
I think it is k=2, if you substitute the range of t into y, the Max you can get is 2 and min is -2


I get it now, thanks :biggrin:

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