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EDEXCEL A2 Physics EXAM Unit 4 Physics On The Move 20th June 2016 (NOT I-A-L)

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i changed the multiple choice sphere charge question at the last second. I circled double both charges because i remember doing a past paper question where one of the charges was halved but angle of point charge remained the same. Therefore had no effect on the force. Had to be both
Original post by KINGYusuf
Conservation of momentum velocity Q anyone get 0.5m/s?

Yep 😀
Then I got it as a Inelastic collision
(edited 7 years ago)
Original post by Ezio.
20.4 m i think wby :smile:


Same :smile:
I got 7.6m or something for the radius? How did yous do it?
Q/m = 4.9 x 10^-5 which is = to 50 micro C
Original post by josephinemar25
Damn it got 33% :frown:


I got 33% too
What did everyone put for the one about is the electron suitable for probing the atom?

I got that the wavelength was something like 2.24*10^something. (Just slightly smaller than the atom spacing).
(edited 7 years ago)
4.5 million something for the electron question?
Original post by lilywatts16
I got 7.6m or something for the radius? How did yous do it?


Resolving vertically and horizontally to find F. Equating it to mv^2/r to find r
Guys for Q11 I got completely stuck then got around 2.1×10-11 i think or ×10-something else.

by doing this:

(I know completely wrong method or I'm just unsure about it)

1/2mv^2 = eV to work out v

Then wavelength = h/p so wavelength = h/mv

Is this the correct method?
Original post by ander101
4.5 million something for the electron question?

Yup
Original post by Mustafa347
Resolving vertically and horizontally to find F. Equating it to mv^2/r to find r


Ahhhh! I forgot to resolve horizontally, how stupid! Only did vertical 😩
Reply 72
Avatar for Qcomber
Qcomber
3
Original post by Connorbwfc
What did everyone put for the one about is the electron suitable for probing the atom?

I got that the wavelength was something like 2.24*10^something. (Just slightly bigger than the atom spacing).

I got slightly under spacing value
What we thinking for an A, ~60?
Original post by KINGYusuf
Guys for Q11 I got completely stuck then got around 2.1×10-11 i think or ×10-something else.

by doing this:

(I know completely wrong method or I'm just unsure about it)

1/2mv^2 = eV to work out v

Then wavelength = h/p so wavelength = h/mv

Is this the correct method?



I think that's correct.
What did you put for the next question?
Original post by lilywatts16
Ahhhh! I forgot to resolve horizontally, how stupid! Only did vertical 😩


You'll still get half the marks, but it's impossible to find r only using vertical components as mg= reaction
Reply 76
Avatar for Maetras
Maetras
9
Original post by Qcomber
I got slightly under spacing value


Same here.
Original post by Qcomber
I got slightly under spacing value


I got slightly under spacing value too, but what does this mean for diffraction?
Original post by KINGYusuf
Guys for Q11 I got completely stuck then got around 2.1×10-11 i think or ×10-something else.

by doing this:

(I know completely wrong method or I'm just unsure about it)

1/2mv^2 = eV to work out v

Then wavelength = h/p so wavelength = h/mv

Is this the correct method?


yep
Original post by Connorbwfc
I think that's correct.
What did you put for the next question?


eV = p^2/2m to find p and sub into de broglie's equation

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