Ha, I see, that must have been very confusing indeed. It is C4 stuff. Confusing if you've never seen it before but alright when you get the hang of it.

Please post a link to the paper if possible :h:

Reply 525

Don Pedro K.

Original post by SeanFM

For the first part of the question, find x and go from there.

test

I'm going to be honest here: I'm confused. Like, I have no clue XD

EDIT: Wait...gimme a sec!!

Reply 526

Kevin De Bruyne

Original post by yuveethini

I can't see a typing error - part b is possible to answer. :h:

what have you tried?

Reply 527

Don Pedro K.

@SeanFM I got e^y = x from y = lnx. Then subbing it into log₂x I get log₂(e^y)...

Reply 528

Kevin De Bruyne

Original post by Don Pedro K.

@SeanFM I got e^y = x from y = lnx. Then subbing it into log₂x I get log₂(e^y)...

See, you can do it, you just need to not give up.

Reply 529

Don Pedro K.

Original post by SeanFM

See, you can do it, you just need to not give up.

Yay

! Thanks Sean :smile:

Reply 530

yuveethini

Original post by SeanFM

I can't see a typing error - part b is possible to answer. :h:

what have you tried?

Yes i have, plus the mark scheme says sinX replaces 2sinXcosX (letting X=x/2), as well as cosX to 1-2sin^2X.
But then i think i just figured it out, however isnt sinX= sinx(x/2)cos(x/2)? :s-smilie:

Reply 531

Don Pedro K.

Original post by yuveethini

Yes i have, plus the mark scheme says sinX replaces 2sinXcosX (letting X=x/2), as well as cosX to 1-2sin^2X.
But then i think i just figured it out, however isnt sinX= sinx(x/2)cos(x/2)? :s-smilie:

sin2x = 2sinxcosx

Therefore,

sinx = 2sin(x/2)cos(x/2) :smile:

Reply 532

Kevin De Bruyne

Original post by yuveethini

Yes i have, plus the mark scheme says sinX replaces 2sinXcosX (letting X=x/2), as well as cosX to 1-2sin^2X.
But then i think i just figured it out, however isnt sinX= sinx(x/2)cos(x/2)? :s-smilie:

Allllmost.

Remember that sin2y = 2sinycos, and you can just replace x by anything (eg in the case above, 2y = x.

Reply 533

Don Pedro K.

Original post by Don Pedro K.

Yay

! Thanks Sean :smile:

@SeanFM This is what the mark scheme says :redface:

Reply 534

jkhan9625

June 2015 questions 2b, draw the equation of asymptote for modulus of fx.
If you take y=5 it cuts the graph, and graphs do not cut their asymptotes, can someone explain this please?

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Reply 535

jkhan9625

ImageUploadedByStudent Room1466422594.202323.jpg

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Reply 536

Kevin De Bruyne

Original post by Don Pedro K.

@SeanFM This is what the mark scheme says :redface:

it seems that they've applied the change of base formula.

Where one of the terms is log to base e, otherwise known as ln.

What question is this from? It's been said that it's not on the spec (which I believe), even though it's in the C2 textbook.

Reply 537

bat_man

question.
if you change the angles inside the double angle identity. for sin(2A) which is 2sinAcosA. if its sin4A.is it 4sin2Acos2A?or 2sin2Acos2A

Reply 538

Kevin De Bruyne

Original post by bat_man

question.
if you change the angles inside the double angle identity. for sin(2A) which is 2sinAcosA. if its sin4A.is it 4sin2Acos2A?or 2sin2Acos2A

It's always 2* if you're halving the angle, no matter what you're halving.

Reply 539

Don Pedro K.

Original post by SeanFM

it seems that they've applied the change of base formula.

Where one of the terms is log to base e, otherwise known as ln.

What question is this from? It's been said that it's not on the spec (which I believe), even though it's in the C2 textbook.