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Edexcel Core 3 - 21st June 2016 AM

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Have arcsin/arcos graphs ever come up?
Original post by Turtlebunny
What answer are you getting?

Make sure that you are also in radians.


0.7514..etc I'm supposed to be getting 0.80219...etc

+ yep, I am. :'3


Original post by ryanroks1
Is your calculator in radians?


yep!
image.png
Original post by BrainJuice
I mean generally, however right now I'm stuck on finding the asymptote of y = 144 - 26e^-2x
Original post by zombaldia
Have arcsin/arcos graphs ever come up?


Yes
Original post by Polyrogue
You mean arcsin, right? Not sin?


No, I had it as sin. :facepalm2: Thank you.

Original post by Economistician
Arcsin and sin are not the same thing.

It should be (arcsin(1-0.5(0.8)))^1/2 which is (inverse sin(1-0.5(0.8)))^1/2


Thank you v much. :'3
Original post by Pablo Picasso
Yes

when did it come up and is arcsin the same an sine inverse
Original post by Anon_98
0.7514..etc I'm supposed to be getting 0.80219...etc

+ yep, I am. :'3




yep!


It's hard to see, but are you taking the inverse sin of 1-0.5(0.8)? Looking at your workings again it dosen't seem so, although I could be mistaken

If that's not the case, can you take a picture of your calculator screen?
Original post by Anon_98
No, I had it as sin. :facepalm2: Thank you.



Thank you v much. :'3


No worries, we all make stupid mistakes haha.
Original post by Turtlebunny
It's hard to see, but are you taking the inverse sin of 1-0.5(0.8)? Looking at your workings again it dosen't seem so, although I could be mistaken

If that's not the case, can you take a picture of your calculator screen?


No, I wasn't.- It was bc I just took it as sin, but it works now.

Thank you. :'3
Original post by flylikeafly
when did it come up and is arcsin the same an sine inverse


y=arcsinx is a one to one function from -1 to 1.
When you have an arcsin in place of a sin, is it the same process, just use sin^-1(number) to find the angle?
https://b3755649dbd1afe3db91a899c3b9837b22326254.googledrive.com/host/0B1ZiqBksUHNYMG14YWtobVJUUms/for-Edexcel/Solomon%20H%20QP%20-%20C3%20Edexcel.pdf

Solomon Paper H
Question 4(b)?
Any ideas? Thanks!
How should anyone revise for this exam have no clue what to do
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joodaa
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Original post by badaman

I'd use the points they have already given you to make two simultaneous equations
Can someone explain how their working gives the range? I understand the one where you use x = 0, but I don't get the second one. Do you sub in a massive value to find the asymptote, which is the min value for the range? @13 1 20 8 42


Capture.JPG
Reply 815
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-Bex-
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Original post by badaman




subbing the stationary points into formula (y = a+bcosecx) gives:

-1 = a+b(1)
-5 = a+b(-1)

as: cosec(π/2) = 1cosec(2π/3) = -1



then it's just a simultaneous equation
Don't think you should really be asking that the night before the exam...

But since you are just do past papers
e^x+3e^-x=4. Why can't I do:

x+ln(3)+ln(e^-x)=ln(4)

x-x=ln(4/3)

My x's keep cancelling out :s-smilie:
Original post by flylikeafly
How should anyone revise for this exam have no clue what to do


Um, well personally I'm just doing a past paper + posting here everytime I get stuck/find the mark schemes aren't helpful enough. :tongue:

Perhaps also use exam solutions if you really don't understand a topic/something?

Repeat until bedtime?
Original post by badaman


You are given some coordinates that lie on the graph.

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