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Edexcel Core 3 - 21st June 2016 AM

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I think one of the hardest things about this paper was how quick you had to be, jesus, i was practically out of breath
I think its time to take action against edexcel
What was your smallest possible value for theata?
Original post by Michaelj99
yessss i remember getting 33.0 :biggrin: and it was something along those lines


Yes! 33 and 274 something
Q1a, x=6, x=-5
b. a=6
2a. dy/dx = (20-4x^2)/(x^2+5)^2
b. x>rt(5) x<-rt(5)
3a. rt(5)cos(theta +26.57)
b. theta = 33.0, 273.9
c. theta = 86.1
4a. y=21, x=ln(2.5)
y=25 (k=25)
b. Proof
c. x1= 1.4368
x2= 1.4373
d. Show the change in sign. (gradient function)
5i. Turning points: 0.9463
ii. 0.5cosec(4y)
6a. A=3 B=4
b. x+2y-35=0 (or equivalent)
7a. arcsin(x) graph
b. x= -(2+rt(3))/2
8a. Proof
b. x= 0.294, -1.277, 1.865 and 1 more I think
9a. 6.740
b. Proof
c. T = 5ln(2+(2/e))
How do we start a petition to lower the grade boundary?
Reply 1246
Original post by mk_98
What did everyone get for the value of k (asymptote) on the graph. I got 21


I got 21 as my value of Y where x=0 , My value of k was 25
I did fcking partial fractions for that question and got 13 and 20, really messed that up :/ , can anyone tell me how many marks the question was out of/ how many marks I'd get for doing the second part of the question but with what I'd worked out
Did question 2 simplify after finding dy/dx!??!?!??!

What the **** ..everything else was alright that ****er got me
Y intercept 21 k was 25
Edexcel wants beef
Original post by AQATrolledMe
How do you show that the amount of antibiotics left wass 13. something?


If you mean on 9b, you had to do

15e^-0.2(7) + 15e^-0.2(2) to get what's left of the first dose after 7 hours (the first five then the two after the second dose) added to what's left of the second dose after 2 hours. Not totally sure about the formula/model but I think that was the right method.
What was the range for question 8
Original post by blahblah21
Q1a, x=6, x=-5
b. a=6
2a. dy/dx = (20-4x^2)/(x^2+5)^2
b. x>rt(5) x<-rt(5)
3a. rt(5)cos(theta +26.57)
b. theta = 33.0, 273.9
c. theta = 86.1
4a. y=21, x=ln(2.5)
y=25 (k=25)
b. Proof
c. x1= 1.4368
x2= 1.4373
d. Show the change in sign. (gradient function)
5i. Turning points: 0.9463
ii. 0.5cosec(4y)
6a. A=3 B=4
b. x+2y-35=0 (or equivalent)
7a. arcsin(x) graph
b. x= -(2+rt(3))/2
8a. Proof
b. x= 0.294, -1.277, 1.865 and 1 more I think
9a. 6.740
b. Proof
c. T = 5ln(2+(2/e))


Correct me if im wrong please (:
Original post by mk_98
What did everyone get for the value of k (asymptote) on the graph. I got 21


I got 25
Original post by chloeabeki
I got 25, think I got 21 for the y intercept though?

Asymptote was 25 and y intercept was 21
Original post by Ecomaths
How do we start a petition to lower the grade boundary?


Go on change.org
Original post by Ecomaths
How do we start a petition to lower the grade boundary?


We don't.
Original post by seard007
Easiest paper in years - why have edexcel dumbed down their maths papers this year?


Original post by SeanFM
There's no need to be obtuse.


[if you'll pardon the pun] :biggrin:
Put together an unofficial mark scheme, feel free to comment if I'm wrong anywhere
http://www.thestudentroom.co.uk/showthread.php?t=4178403&p=65974317#post65974317

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