AQA MM1B - Mechanics 1 -Tuesday 21st June 2016

did people get 8 for the bearing?

How did you do the finding the angle of the ramp question? I did some weird thing where I cancelled mass, (f=ma), probably didn't work.

13.6 I think not 100% sure

What did you get for t in the first question.

Posted from TSR Mobile

yeah i did same ,I think thats the right way to do it

My answers, no idea how many are right:

Question 1 (Momentum)

0.4m/s
15kg

Question 2 (Particles/Vectors)

P=14
Q=-17

(16i-8j)

Question 3 (Toy Car on Slope)

1.5ms^2
1.8m/s
9°

Question 4 (Airplane)

V = 12m/s
Resultant = 90.8m/s
008°

Question 5 (Connected Particles)

3.92ms^-2
2.50m/s
1.12m

Question 6 (Cleaning Device at 60°)

Tsin60+5g
T=43.8N

Question 7 (Football Projectile)

1.76s
13.6m
13.2m/s
No air resistance

Question 8 (Helicopters)

80.5m


Posted from TSR Mobile

My answers, no idea how many are right:

Question 1 (Momentum)

0.4m/s
15kg

Question 2 (Particles/Vectors)

P=14
Q=-17

(16i-8j)

Question 3 (Toy Car on Slope)

1.5ms^2
1.8m/s
9°

Question 4 (Airplane)

V = 12m/s
Resultant = 90.8m/s
008°

Question 5 (Connected Particles)

3.92ms^-2
2.50m/s
1.12m

Question 6 (Cleaning Device at 60°)

Tsin60+5g
T=43.8N

Question 7 (Football Projectile)

1.76s
13.6m
13.2m/s
No air resistance

Question 8 (Helicopters)

80.5m


Posted from TSR Mobile

I got 12s sorry Im stressing now haha because vectors will be parallel when vector a is a multiple of vector b

I got 1.98 seconds

Could you tell me how you worked it out?

well i used t=5 because only the i component of the velocity is the same therefore i subbed 5 into the r=ut+1/2at^2 of the A and the r=ut+1/2at^2 + r original of the B then i subtracted the two r from each other to get the distance then i added the square of the i component and the square of the j component and square rooted the answer. Its really hard to explain it without paper and pen I'm not even sure of my answer lol