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Edexcel Core 3 - 21st June 2016 AM

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I found that really hard but the consensus was that it wasn't impossible but a 7/10 for difficulty.

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Reply 1321
can anyone remember the range and number of solutions for the tan4x question?
Reply 1322
Original post by Michaelj99
8b) 6cot2x+3tanx=Cosec^2x-1 -------------> 3Cotx=1+cot^2x-2------> Cot^2x-3Cotx-1=0 and then quadratic formula. anyone remember the range? i only got 3 solutions i believe


was 4 solutions
Original post by blahblah21
Q1a, x=6, x=-5
b. a=6
2a. dy/dx = (20-4x^2)/(x^2+5)^2
b. x>rt(5) x<-rt(5)
3a. rt(5)cos(theta +26.57)
b. theta = 33.0, 273.9
c. theta = 86.1
4a. y=21, x=ln(2.5)
y=25 (k=25)
b. Proof
c. x1= 1.4368
x2= 1.4373
d. Show the change in sign. (gradient function)
5i. Turning points: 0.9463
ii. 0.5cosec(4y)
6a. A=3 B=4
b. x+2y-35=0 (or equivalent)
7a. arcsin(x) graph
b. x= -(2+rt(3))/2
8a. Proof
b. x= 0.294, -1.277, 1.865 and 1 more I think
9a. 6.740
b. Proof
c. T = 5ln(2+(2/e))


Do you remember the range of x for q. 5(i)??
What was the first part of the first question as i think i might have misread it ?
Can anyone remember the marks for each question part???
For 7b if I left my answer as sin(-pi/3) -1 which is the same answer as your value for x would I still get full marks?
Reply 1327
Original post by KellyLouise0
anyone remember the number of marks for the proof of root in the interval question? (last part of Q4, i think)
I ****ed up, couldn't find a sign change :frown: any marks for just stating the interval to be used at all?

don't think so
Original post by d14m
can anyone remember the range and number of solutions for the tan4x question?


i think it was between pi/2 and pi/4
Reply 1329
Original post by nadz_98
For 7b if I left my answer as sin(-pi/3) -1 which is the same answer as your value for x would I still get full marks?


doubt it
Anyone know what Question 3 asked?
(the one with k, a and y). 4e^2x-24 or something
Reply 1331
Other then 7b i got the same as u! So i hope ur right looool
Original post by blahblah21
Q1a, x=6, x=-5
b. a=6
2a. dy/dx = (20-4x^2)/(x^2+5)^2
b. x>rt(5) x<-rt(5)
3a. rt(5)cos(theta +26.57)
b. theta = 33.0, 273.9
c. theta = 86.1
4a. y=21, x=ln(2.5)
y=25 (k=25)
b. Proof
c. x1= 1.4368
x2= 1.4373
d. Show the change in sign. (gradient function)
5i. Turning points: 0.9463
ii. 0.5cosec(4y)
6a. A=3 B=4
b. x+2y-35=0 (or equivalent)
7a. arcsin(x) graph
b. x= -(2+rt(3))/2
8a. Proof
b. x= 0.294, -1.277, 1.865 and 1 more I think
9a. 6.740
b. Proof
c. T = 5ln(2+(2/e))
I left out #3c ****ing hell. How many marks were there in #3c?
Original post by Yua
was 4 solutions


ah oops
Original post by KellyLouise0
anyone remember the number of marks for the proof of root in the interval question? (last part of Q4, i think)
I ****ed up, couldn't find a sign change :frown: any marks for just stating the interval to be used at all?

I couldnt get a change of sign but you get a mark for using the upper and lower bounds .
My friend did it and you had to take away 2x + 43 away from the gx at the beginning of the equation, then sub the values into that.
Original post by Aprkrheiqkk
Do you remember the range of x for q. 5(i)??


-pi to +pi
Original post by thehollowcrown
i got 0.1609 for the turning point question, other people have been saying different, so now i'm like shizzz was my calculator in the wrong setting

The turning point had to be between pi/4 and pi/2 so the answer was 0.9 something :/
Original post by blahblah21
Not too sure its one of the 2, because I remember seeing 32 and 3, so I think 1 of us just read the signs wrong, worst case one of us will lose 2 marks

I got 35/2 if it makes you feel any better
That was an X point but it didn't lie in the domain, u had to use a cast diagram to find another solution being 0.9643

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