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Edexcel C3 June 2016 - Unofficial Mark Scheme

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Reply 20

cookie_raider01

[QUOTE=veldt127;65974317
ii ln(2.5)

wasn't 4ii 0.5ln(2.5)

because 2x= ln(2.5)
so x= 0.5ln(2.5)

Reply 21

heyitskim

For 8b how many marks will I lose if I left the answers in degrees and not radians

Reply 22

Mattematics

Original post by mk_98

It was - 4x^2+20 wasn't it? Otherwise how would you get the range of values for the second part?

https://www.wolframalpha.com/input/?i=(20-4x%5E2)%2F(x%5E2%2B5)%5E2

The answer in the original post is correct. It can't be simplified any further.

Reply 23

ZeroShun

How much was question 2b worth

Reply 24

Gouber

And what was question 5i ?

Also anyone remembers how many marks
5i, 5ii is worth?

Reply 25

Mattematics

Original post by cookie_raider01

ii ln(2.5)

wasn't 4ii 0.5ln(2.5)

because 2x= ln(2.5)
so x= 0.5ln(2.5)

4e^2x - 25 = 0
e^2x = 25/4
e^x = 5/2
x = ln(5/2)

Reply 26

marethyu

What was question 3b and 3a? the questions not answers

Reply 27

unimaginable118

Does anyone remember how many marks the last question was? I was SO STUPID. I left it out :frown:

(( looks like someones not going to uni...

Reply 28

theereflex

For 3(c), I don't understand why the lowest value of theta wasn't just 33 from part b?

anyone help?

Reply 29

jovdawesome

how much do i have to pay if i want to retake c3 next year ?

Reply 30

jakelong1001

Original post by particlestudent

Im sure only the middle two values were allowed for 8B

No, the interval was -pi<x<pi

Reply 31

wedge16

Original post by theereflex

For 3(c), I don't understand why the lowest value of theta wasn't just 33 from part b?

anyone help?

In part b you solved for when sin theta was negative, in part c however sin theta was positive

Reply 32

jakelong1001

Original post by theereflex

For 3(c), I don't understand why the lowest value of theta wasn't just 33 from part b?

anyone help?

I asked someone about this, apparently the equation showed on part C was not the same equation as part a, there was a negative sign added somewhere so you had to equate it again and get a different value for the angle.

Hope this helped

Reply 33

cookie_raider01

Original post by jovdawesome

how much do i have to pay if i want to retake c3 next year ?

its around £34 for 1 retake as you have to take it outside school so the school doesn't subsidise.

Reply 34

theereflex

Really? That's what I was expecting so I checked the equations over and over, ... and I still missed it, wow

thanks

Reply 35

cheesedrew

Original post by DomWoodcock

Yeah I think I remember the limits between -pi/2 and pi/2

i recall that also so i only had two angles

Reply 36

theereflex

anyone remember what question 6 was?

Reply 37

sierra117

Original post by Dieselblue

For 5i what did people do with the sin and cos?

Also part 2a is wrong, -4x^2-20=-4(x^2+5) so -4/x^2+5

I believe you're wrong. It was -4x^2 + 20, not -20. Therefore the answer stated by this post is correct.

Reply 38

Narxs

Original post by Mattematics

4e^2x - 25 = 0
e^2x = 25/4
e^x = 5/2
x = ln(5/2)

I did 4e^2x =25
e^2x=25/4
2x=ln(25/4)
x=0.5ln(25/4)

But didn't simplify ant further would this be alright??

Reply 39

unimaginable118

Original post by marethyu

a 2
b 2
c 4
8 in total

Totally saying goodbye to any chances of an A ......

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