Edexcel C3 June 2016 - Unofficial Mark Scheme

Hopefully you don't lose a mark for leaving it as 1/2ln(25/4)

Any one remember the boundaries for question 8 as pi/4<X<pi/2 or something like that

I'm not 100% sure on all of these, but I think most are correct.

Question 1Question 2Question 3Question 4Question 5Question 6Question 7Question 8Question 9PDF with working for 1-4 and 9 : http://www.thestudentroom.co.uk/attachment.php?attachmentid=554155&d=1466508775

That's what I got, no idea if you need both or if either would do.

Can't even remember the question

No if I remember the gradient was 2 when you put x=3 into dy/dx. Then it was asking for the normal so m = -1/2.

2y-32 = -1 (x-3)
2y-32=-x+3
x+2y-35 = 0 for the full 5 marks.

I got A=-5 for the last question. Did I do something wrong or is there a typo?

Oh nooooooo, I think I had a + instead of a - using the quotient rule... That'll be what 2 marks gone?

I think u made the mistake when the "e" bit of the term was flipped. Maybe u didn't change the sign of the power after flipping it.

does anybody know how many marks question 9 was worth? i didn't see it so i missed the entire question

F********K.

Omg for 3.a. I got r=root(5) , and I got a=63.43...

I got the value of 'a' wrong and I used this value for the rest of my question!!!!!
How many marks would I lose if I got the method correct?

Thats what i got too, why would it be 0.9somethin?

I don't think question 5ii is correct. I think it's -0.5 because we had to differentiate cosx which mean that the term became negative. So I think it should be -0.5 instead of 0.5

I got a gradient of the tangent as 10, so the gradient of the normal was -1/10, I think I got y-16=-1/10(x-3) and then simplified, I don't think you need to simplify it though as it didn't say in the question so leaving it in that form would be fine I guess

Your welcome how did everyone find the exam today question 8 was particularly troublesome but the rest of the questions weren't too bad.

Hopefully you don't lose a mark for leaving it as 1/2ln(25/4)

ok guys so i have a question about how many marks i'd get for question 6, where you had to find the values of A and B and then the eqn of the normal.

I tried part a properly a few times and could not get it for some reason, but then i looked at part b. i noticed if you differentiated the given function then you'd get rid of A. I put the original eqn into my calculator to find the gradient of the tangent at the point (2), then obviously found the normal gradient and equation.
Through this i could create and equation for B, so work out that B=4. then just sub this into the original eqn to find A=3. i just wrote 'comparing coefficients gives...' for the 'working' (though I didn't cross anything out, but i'm pretty sure it was all wrong anyway)

obviously this is a very dodgy method, how many marks am I looking at? thanks.