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OCR A2 CHEMISTRY F324 and F325- 14th and 22nd June 2016- OFFICIAL THREAD

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Original post by Ezexamsalltheway
HI , guys how many of the transition metal aqueous ion colours do we actually need to know. all of them? thought i should better start my revision now :P rip


Copper
(Blue) Cu2+ or [Cu(H2O)6]2+
(Light blue) Cu(OH)2 (s)
(Yellow) [CuCl4]2- (this one looks green if you don't have excess Cl-
(Deep blue) [Cu(NH3)4(H2O)2]2+

Spoiler


Cobalt
(Pink) Co2+
(Blue) [CoCl4]2-
(Blue) Co(OH)2

Spoiler


Iron
(Pale Green) Fe2+
(Green) Fe(OH)2
(Yellow) Fe3+
(Brown) Fe(OH)3

Chromium (as in alcohol oxidation reactions)
(Green) Cr3+
(Orange) Cr2O72-

Manganese
(Purple) MnO4-
(Pink, colourless) Mn2+

And the colour changes with thiosulfate and iodine in the clock reaction. Not transition elements, but useful to know.

Spoiler

is 2nd equation so charges on right = charges on left? https://gyazo.com/7d6e8331e15fc94e20faa04b0f006cef do i have to do that with all ionic equations?
Original post by RayMasterio
Yes - you can get an optical isomer. It's literally a mirror image of the trans!


But that's the thing, the mirror image of the trans will look exactly the same as the trans...., I guess they will rotate plane-polarised light in different directions so they wouldn't be the same molecule but the molecules appear to occupy the same spaces (from the diagrams at least).
Original post by lai812matthew
that's what i write


do you have to be specific and say two, what if you say bacteria produced one and lab produces many i.e. more than one, do you have to specify 2
How do you know if an indicator is suitable for a certain acid-base titration?
Original post by ImNervous
Do we need to know anything about electrolytic cells or do we need to know both?

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No optical isomers of the trans form.


No we don't need to know about electrolyte cells, yeh that's what I thought.
Original post by Roses98
I don't think the red colour is what's useful to deduce the formula. The VI is the critical information. It tells you about the oxidation state of Fe. VI means +6. Plugging this in and considering the overall -2 charge should help you work it out.

If the question were to say IV or V, you can deduce that Fe would be +4 or +5 oxidation state respectively. :smile:

Yeah I know that.

I was asking the OP what the VI stood for? To check they understand?

I hadn't realised that they had given roman numerals when I first saw the question
Original post by lai812matthew
like there is only [Fe(NH3)4(H2O)2]n+ complexes but not [Fe(NH3)6]n+ complexes.


Is that just memory or should we know why that doesn't occur?


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Original post by M.Branson98
How do you know if an indicator is suitable for a certain acid-base titration?


If the peak of the acid is high then there's a strong base, if the bottom curve is low there's a strong acid.

Indicators will have their range given so you just have to see if it falls in the range right?


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Original post by mechanism
Do we have to know about half neutralisation?


what's that??
I'm so nervous for this exam. I just can't to the calculations towards the end of the paper. I'm so tired I keep making stupid mistakes. Bye bye a*
Original post by tcameron
what's that??


To do with acid and bases where HA=A-.
How would you conduct an experiment to measure enthalpy of solution (4 marks)
Original post by lai812matthew
my last attempt on A* after i flopped f324 if this doesn't go well i'll have no uni to go to.......


Same.... F324 was too wordy for me, I wanted more synthesis and a long NMR. I made many incredibly silly errors - I completely ignored the carbon-13 spectrum until I left the exam hall and realised why it was there etc.... F325 tends to go better for me. More maths = more marks haha. Good luck!
Original post by mechanism
To do with acid and bases where HA=A-.


how does that work? Why would it be only a jhalf neutralisation
Original post by ToLiveInADream
How would you conduct an experiment to measure enthalpy of solution (4 marks)


you can't measure the lattice enthalpy directly so how would that work?
Original post by tcameron
how does that work? Why would it be only a jhalf neutralisation

This is what I'm confused about, however I think I get it - when half of HA reacts, that amount of A- has been formed. so the [HA] left = [A-] formed
Original post by M.Branson98
How do you know if an indicator is suitable for a certain acid-base titration?


find the pH range of the indicator - say for example it's given as 4.0 - 8.0. Then look at the curve for the acid base titration and spot the end point - so like the centre of the sharp upward line where neutralisation occurs. If the end point lies about the middle of the pH's range (so around 6.0 in this case) then it's suitable
Original post by tcameron
anyone have a proper definition of Kstab? The one in the book makes no sense to me


It's basically Kc without water, the higher the kstab the more stable a complex is.
Can somebody run through those standard 3 markers on energy comparisons of e.g. RbF vs RbCl or MgCl2 vs NaCl Usually accompanied by a table with some enthalpy values of hydration/solution/lattice enthalpy.

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