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Edexcel A2 Chemistry Exams -6CH04 (14th June) and 6CH05 (22nd June) Discussion Thread

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Original post by lfcrules
oh **** , i just described recrystallization


i did recrystallisation as well?
Original post by lfcrules
oh **** , i just described recrystallization


it was recrystallisation
Original post by lfcrules
oh **** , i just described recrystallization


Pretty sure it was recrystallisation as it mentioned the purified 'solid'.
on the last question did you protonate both NH2 groups or just the one?
Original post by nicklongy
Recrystallisation is correct, it was purifying an impure solid

Yes!
What did everyone do for the vanadium ions 5 marker?
YAYYYYYYYY it was recrystalization!!!!!!!!!! . How are you meant to dry the solid , i just mention suction filtration with a buchner funnel and adding anhydrous calcium chloride?
which were the conjugate acids and bases?
Original post by Funky_Giraffe
on the last question did you protonate both NH2 groups or just the one?


I protonated both groups . You werent meant to deprotonate the oh group on the molecule with nh2 on were you , just the other molecule was deprotonated?
what did you guys put for that wierd benzene mcq , i did the one about ti having a lower enthalpy level or something
(edited 7 years ago)
Original post by lfcrules
I protonated both groups . You werent meant to deprotonate the oh group on the molecule with nh2 on were you , just the other molecule was deprotonated?


Not sure what you mean. The COOH group would have gone to COO-
Original post by Footyrulez
i did recrystallisation as well?


Oh ****! then
Original post by Footyrulez
What did everyone do for the vanadium ions 5 marker?


First reaction with Iodide ions was feasible to get VO2+, Ecell around +0.46 I think?


Second reaction was not feasible Ecell -0.20V so remained at V(IV)
what was the equation for CuCl2 with HCl and Cu(s) ?
Original post by nicklongy
First reaction with Iodide ions was feasible to get VO2+, Ecell around +0.46 I think?


Second reaction was not feasible Ecell -0.20V so remained at V(IV)


Ah thats what I got as well!! :smile:
feel like you can do both separating funnel and recrystallization, similar q came up ive seen and it was about purification with sodium hdrogencarbonate to remove acid then separate and distill then add anhydrous calcium chloride
Original post by lfcrules
oh **** , i just described recrystallization


I did too
Original post by Funky_Giraffe
Not sure what you mean. The COOH group would have gone to COO-


the molecule with the amine groups on also had an oh group on . The oh group didnt lose a proton did it ?
5 mark calculation 95.13% anyone?
Original post by Funky_Giraffe
what was the equation for CuCl2 with HCl and Cu(s) ?


Cu2+ + Cu + 4HCl = 2(CuCl2)- + 4H+ ?

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