i got 0.439 days or something but it said to give it to the nearest min not to convert to mins. e.g like 0.5435 km is 0.544 km to the nearest m did you have to convert to mins?
8) {3,5,0}, r = {1,5,2} + lambda{-5,4,3}, k=2, cos(theta)=4/5, area=12/5, possible positions {3, 33/5, 16/5} and {-1, 17/5, 4/5}
Fairly sure E is actually (3, 17/5, 4/5) or (-1, 33/5, 16/5) or otherwise it doesnt fit on the line L2. E = (1,5,2)+k(-5,4,3) so 1-5k=3 --> k= -2/5 5 + 4 x -2/5 = 17/5 2 + 3 x -2/5 = 4/5
You can do the same for the other value of E to work out if its on the line
The exam went really well for except for the last 5 marker, could someone please explain to me how you were meant to do it as i literally spent about 25minutes on it and knew i had done one similar in the past. I was using the fact P was the midpoint and magnitudes were 2root2. But was proberly going off on a tangent