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Help with Q6 from the C4 exam?

In question 6! i cant remember the exact question but think it was:

u = 4sin^2(x)

prove = integral (4/(1-4x)^1/2 is same as (k integral sin^2(u)) where you must find k.

the prove that the integral = k (integral) sin^2x i got 1/8 (integral) sec^2x.

Where did i go wrong and how many marks would i have got for the follow up question if i used k= 1?8 instead of k =8?
(edited 7 years ago)
Reply 1
Original post by twigface
In the prove that the integral = k (integral) sin^2x i got 1/8 (integral) sec^2x.

Where did i go wrong and how many marks would i have got for the follow up question if i used k= 1?8 instead of k =8?


Your question doesn't make sense as it stands, please edit and clarify.
Reply 2
Original post by twigface
In the prove that the integral = k (integral) sin^2x i got 1/8 (integral) sec^2x.

Where did i go wrong and how many marks would i have got for the follow up question if i used k= 1?8 instead of k =8?


you mean lambda not k right? all the method marks minus accuracy if you did it right
Reply 3
Original post by WillRose
you mean lambda not k right? all the method marks minus accuracy if you did it right


yeah i think so.

do you remember what the question was?
Reply 4
Original post by Zacken
Your question doesn't make sense as it stands, please edit and clarify.


ok written out the question
Reply 5
Original post by twigface
yeah i think so.

do you remember what the question was?


so probably 4/5?
Reply 6
Original post by WillRose
you mean lambda not k right? all the method marks minus accuracy if you did it right


actually refresh if you've seen this as i have edited
Not sure how you got sec^2T

The 8 came from the dx/dT where T = theta
I can't really remember the question but I remember something along the lines of tanx*8sinx*cosx I can't remember what was squared and what wasn't

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