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Edexcel S2 - 27th June 2016 AM

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Original post by Lilly1234567890
if i have like three functions of CDF
and i want to find the mean which function do i choose to equal to 0.5?


I just use trial and error lol, if you've picked the wrong one then the x value you get won't make sense ☺️ I'd be interested to hear if anyone had a better system though!
Original post by Patrick Gekko
I got the answer in the MS


How?

I have the same working out as the mark scheme but a different answer
Someone quickly help me pls....

https://57a324a1a586c5508d2813730734691051ac35fd.googledrive.com/host/0B1ZiqBksUHNYZ3M4QzJ0N19IeHc/January%202009%20QP%20-%20S2%20Edexcel.pdf

3a. Im getting x<<1 and x>>2
Original post by Lilly1234567890
if i have like three functions of CDF
and i want to find the mean which function do i choose to equal to 0.5?


Are you asking about the median? You cannot find the mean in that way.
Original post by khaleesi98
I just use trial and error lol, if you've picked the wrong one then the x value you get won't make sense ☺️ I'd be interested to hear if anyone had a better system though!


I usually test the upper bound of the second function, since it probably wont be in the first function so testing that boundary tells whether its the second or the third.

Such a small thing, but I think it saves a bit of time.
Original post by RetroSpectro
How?

I have the same working out as the mark scheme but a different answer


Really? If you've got the same working as the MS then I'm not sure what has gone wrong.

Obviously X is binomially distributed (120,0.008)
You want the probability of there being at most 1 cracked egg, so this is P(x=0) + P(x=1)

Then just use the formula in the formula book and you should get it..
Original post by mangoli
Give me an easy and intuitive way to remember the skewness of a PDF please :u:


If you have the S1 textbook, there's like a page describing everthing.

I just like to remember that mode < median < mean => positive skew, the opposite is negative.

Mode, median, mean. Easy list to remember (in that order).
Original post by RetroSpectro
How?

I have the same working out as the mark scheme but a different answer


Liink the MS pls
Original post by SeanFM
Are you asking about the median? You cannot find the mean in that way.


I thought if a CDF is symmertical then the median=mean?
Original post by mangoli
Give me an easy and intuitive way to remember the skewness of a PDF please :u:


Way i remembered it in S1 is mean,median,mode: the mean wants to be as 'mean' as possible so when its bigger than the median and mode its positive (skew).

It's an odd way to remember, but if it works, how odd really is it...
Original post by Patrick Gekko
Really? If you've got the same working as the MS then I'm not sure what has gone wrong.

Obviously X is binomially distributed (120,0.008)
You want the probability of there being at most 1 cracked egg, so this is P(x=0) + P(x=1)

Then just use the formula in the formula book and you should get it..


Oh i think entering 120C0 in my calculator without brackets mixed up the order of the processes hence why i got a different answer.

Thanks anyway
Hardest S2 papers please? X

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https://57a324a1a586c5508d2813730734691051ac35fd.googledrive.com/host/0B1ZiqBksUHNYZ3M4QzJ0N19IeHc/January%202009%20QP%20-%20S2%20Edexcel.pdf

Q4d and e?
Original post by undercxver
I thought if a CDF is symmertical then the median=mean?



Let's see with an example.

If we had pdf = x for 0 <= x < 0.5 and 1-x for 0.5 <= x < 1 then the mode is 0.5.

The CDF is x^2/2 for 0 <= x < 0.5 and x - (x^/2) + (1/8) for 0.5 =< x < 1 so the median is indeed the mode.

The mean is integral of x between 1 and 0 which is 0.5.. so mode = median = mean. So we have shown that there is in fact no skew when all 3 of these things are true :lol:

But when there is skew, the mode is not equal to the median, which is not equal to the mean.

But you are right :h:
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taysc
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Original post by themathgeek
hardest s2 papers please? X

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june 14 r
Reply 535
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JASISR
4
Could someone please help me with 5d on the June 2015 paper, thank you
https://57a324a1a586c5508d2813730734691051ac35fd.googledrive.com/host/0B1ZiqBksUHNYZ3M4QzJ0N19IeHc/June%202015%20QP%20-%20S2%20Edexcel.pdf
(d) find the probability that the residents do not pay more than £500 to Liftsforall in thenext year.
Picture1.png410.4KB
For anyone struggling to remember skews in a pdf use:

PMQU

P - M < Q < U

Positive - mode < Quartile 2 (median) < mu (mean)

and for a negative skew its the opposite direction
https://57a324a1a586c5508d2813730734691051ac35fd.googledrive.com/host/0B1ZiqBksUHNYZ3M4QzJ0N19IeHc/January%202009%20QP%20-%20S2%20Edexcel.pdf

6c. Why have they used normal distribution?
Any thoughts on tomorrow's paper? - Hopefully it's going to be a 6 Question paper ending on a nice easy mean or median sampling distribution :smile:
Original post by fpmaniac


The only Approximation that can be used for a Poisson distribution is a normal approx.

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